95.將阿拉伯?dāng)?shù)字轉(zhuǎn)換為羅馬數(shù)字

將大于0小于1000的阿拉伯?dāng)?shù)字轉(zhuǎn)換為羅馬數(shù)字。阿拉伯?dāng)?shù)字與羅馬數(shù)字的對(duì)應(yīng)關(guān)系如下：

*問(wèn)題分析與算法設(shè)計(jì)

題目中給出了阿拉伯?dāng)?shù)字與羅馬數(shù)字的對(duì)應(yīng)關(guān)系，題中的數(shù)字轉(zhuǎn)換實(shí)際上就是查表翻譯。即將整數(shù)的百、十、個(gè)位依次從整數(shù)中分解出來(lái)，查找表中相應(yīng)的行后輸出對(duì)應(yīng)的字符。

*程序與程序設(shè)計(jì)

#includevoid?main()

{

static?char?*a[][10]={"","I","II","III","IV","V","VI","VII","VIII","IX"

"","X","XX","XXX","XL","L","LX","LXX","LXXX","XCC",

"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"

};???????????/*建立對(duì)照表*/

int?n,t,i,m;

printf("Please?enter?number:");

scanf("%d",&n);???????????/*輸入整數(shù)*/

printf("%d=",n);

for(m=0,i=1000;m<3;m++,i/=10)

{

t=(n%i)/(i/10);????????/*從高位向低位依次取各位的數(shù)字*/

printf("%s",a[2-m][t]);??????/*通過(guò)對(duì)照表翻譯輸出*/

}

printf("\n");

}

*運(yùn)行結(jié)果

1.?Please?enter?number:863

863=DCCCLXIII

2.?Please?enter?number:?256

256=CCLVI

3.?Please?enter?number:355

355=CCCLV

4.?Please?enter?number:522

522=DXXII

5.?Please?enter?number:15

15=XV

*思考題

輸入正整數(shù)N，產(chǎn)生對(duì)應(yīng)的英文數(shù)字符串并輸出，例如：

1???????ONE??????2???TWO??????3???THREE

10??????TEN??????11??ELEVEN

135?????ONE?HUNDRED?THIRTY?FIVE

總結(jié)

以上是生活随笔為你收集整理的罗马数字转换成数字java_C趣味编程百例(31)将阿拉伯数字转换为罗马数字的全部?jī)?nèi)容，希望文章能夠幫你解決所遇到的問(wèn)題。

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