c++語句switch語句

The error: case label not within a switch statement occurs in C language with switch case statement, when switch (variable/value) statement is terminated by the semicolon (;).

錯誤：當switch(變量/值)語句由分號( ; )終止時，C語言中的case標簽使用switch case語句以C語言出現。

Example:

例：

#include <stdio.h>int main(void) {int choice = 2;switch(choice);{case 1:printf("Case 1\n");break;case 2:printf("Case 2\n");break; case 3:printf("Case 3\n");break; case 4:printf("Case 4\n");break; default:printf("Case default\n");}return 0; }

Output

輸出量

prog.c: In function ‘main’: prog.c:9:6: error: case label not within a switch statementcase 1:^~~~ prog.c:11:10: error: break statement not within loop or switchbreak;^~~~~ prog.c:12:6: error: case label not within a switch statementcase 2:^~~~ prog.c:14:10: error: break statement not within loop or switchbreak;^~~~~ prog.c:15:6: error: case label not within a switch statementcase 3:^~~~ prog.c:17:10: error: break statement not within loop or switchbreak;^~~~~ prog.c:18:6: error: case label not within a switch statementcase 4:^~~~ prog.c:20:10: error: break statement not within loop or switchbreak;^~~~~ prog.c:21:6: error: ‘default’ label not within a switch statementdefault:^~~~~~~

How to fix?

怎么修？

See the statement switch(choice); it is terminated by semicolon (;) – it must not be terminated. To fix this error, remove semicolon after this statement.

參見語句switch(choice); 它以分號( ; )終止–一定不能終止。 要解決此錯誤，請在此語句后刪除分號。

Correct code:

正確的代碼：

#include <stdio.h>int main(void) {int choice = 2;switch(choice){case 1:printf("Case 1\n");break;case 2:printf("Case 2\n");break; case 3:printf("Case 3\n");break; case 4:printf("Case 4\n");break; default:printf("Case default\n");}return 0; }

Output

輸出量

Case 2

翻譯自: https://www.includehelp.com/c-programs/case-label-not-within-a-switch-statement-error-in-c.aspx

c++語句switch語句

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