##分組取最新的一條數據，錯誤

SELECTa.account_balance,a.deposit_amount,a.deposit_time,a.create_user,a.resident_id,b.resident_code,b.resident_name,b.area_id,c.area_name,a.create_time FROMrevenue_resident_deposit aLEFT JOIN data_resident b ON a.resident_id = b.idLEFT JOIN data_area c ON c.id = b.area_id GROUP BY resident_id ORDER BY deposit_time DESC

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##方法一 分組取最新的一條數據，可行，但LIMIT限定數量100000，數據數量需要計算獲取

SELECTa.account_balance,a.deposit_amount,a.deposit_time,a.create_user,a.resident_id,b.resident_code,b.resident_name,b.area_id,c.area_name,a.create_time FROM(SELECT * FROM revenue_resident_deposit ORDER BY deposit_time DESC LIMIT 100000) as aLEFT JOIN data_resident b ON a.resident_id = b.idLEFT JOIN data_area c ON c.id = b.area_id GROUP BY a.resident_id

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##方法二 分組取最新的一條數據，可行

SELECTa.account_balance,a.deposit_amount,a.deposit_time,a.create_user,a.resident_id,b.resident_code,b.resident_name,b.area_id,c.area_name,a.create_time FROMrevenue_resident_deposit aLEFT JOIN data_resident b ON a.resident_id = b.idLEFT JOIN data_area c ON c.id = b.area_idLEFT JOIN (SELECT MAX(id) id FROM revenue_resident_deposit GROUP BY resident_id) d ON d.id =a.id WHEREa.id = d.id

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##方法三 分組取最新的一條數據，可行

SELECTa.account_balance,a.deposit_amount,a.deposit_time,a.create_user,a.resident_id,b.resident_code,b.resident_name,b.area_id,c.area_name,a.create_time FROMrevenue_resident_deposit aLEFT JOIN data_resident b ON a.resident_id = b.idLEFT JOIN data_area c ON c.id = b.area_idLEFT JOIN (SELECT MAX(deposit_time) dt FROM revenue_resident_deposit GROUP BY resident_id) d ON d.dt =a.deposit_time WHEREa.deposit_time = d.dt

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