意料之中Java會TE

//15分 //最后兩個測試點超時 import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader;public class Main {public static void main(String[] args) throws IOException {//輸入BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));String a[] = bf.readLine().split(" ");int N = Integer.parseInt(a[0]);int M = Integer.parseInt(a[1]);String[][] str = new String[M][N];StringBuffer sb = new StringBuffer("");for (int i = 0; i < M; i++) {str[i] = bf.readLine().split(" ");}//求最大值long[] sum = new long[N];long max = 0;for (int i = 0; i < M; i++) {for (int j = 0; j < N; j++) {long s = Long.parseLong(str[i][j]);sum[j] += s;}}for (int k = 0; k < N; k++) {if (max < sum[k]) {max = sum[k];}continue;}for (int i = 0; i < N; i++) {if (sum[i] == max) {sb.append(i + 1 + " ");}}System.out.println(max);System.out.println(sb.toString().trim());} }

按照原思路用C++敲一遍

//20分 #include <iostream> using namespace std; int main(){int max = 0, N, M, num[1001] = {0}, cnt = 0;cin >> N >> M;for(int i = 0; i < M; i++){for(int j = 1; j <= N; j++){int tmp;cin >> tmp;num[j] += tmp;}}for(int i = 1; i <= N; i++)if(num[i] > max)max = num[i];cout << max << endl; for(int i = 1; i <= N; i++)if(num[i] == max){if(cnt)cout << " ";cout << i;cnt++;} return 0; }

總結

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