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1083. List Grades (25)

發布時間:2023/12/10 编程问答 30 豆豆
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1083. List Grades (25)

時間限制 400 ms
內存限制 65536 kB
代碼長度限制 16000 B
判題程序 Standard 作者 CHEN, Yue

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N name[1] ID[1] grade[1] name[2] ID[2] grade[2] ... ... name[N] ID[N] grade[N] grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are?distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

Sample Input 1: 4 Tom CS000001 59 Joe Math990112 89 Mike CS991301 100 Mary EE990830 95 60 100 Sample Output 1: Mike CS991301 Mary EE990830 Joe Math990112 Sample Input 2: 2 Jean AA980920 60 Ann CS01 80 90 95 Sample Output 2: NONE 解析:本題用的是用空間換時間的策略,所以沒有排序等操作。應用的是HASH思想,運用HASH思想一個關鍵是數組元素的值要和數組元素的下表建立一一影射關系。

/*************************************************************************> File Name: 1083.c> Author: YueBo> Mail: yuebowhu@163.com> Created Time: Sun 14 May 2017 08:26:46 PM CST************************************************************************/#include <stdio.h> #include <stdlib.h> #include <string.h>struct student {char name[16];char id[16];int score; };int main() {int N;int i;char name[16];char id[16];int score, down_score, up_score;int flag = 0;scanf("%d", &N);struct student stu_array[101];for (i = 0; i < 101; i++){stu_array[i].score = -1;}for (i = 0; i < N; i++){scanf("%s%s%d", name, id, &score);stu_array[score].score = score;strcpy(stu_array[score].name, name);strcpy(stu_array[score].id, id);}scanf("%d%d", &down_score, &up_score);for (i = 100; i >= 0; i--){if (stu_array[i].score >= down_score && stu_array[i].score <= up_score){printf("%s %s\n", stu_array[i].name, stu_array[i].id);flag = 1;}}if (flag == 0)printf("NONE\n");return 0; }

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