例如現在有這樣一個Json

String?Value = ?{"data":[{"school_name":"西北農林科技大學","school_id":"8"},{"school_name":"西北大學","school_id":"6"},{"school_name":"西北工業大學","school_id":"5"},{"school_name":"西北政法大學","school_id":"2"},{"school_name":"西安交通大學","school_id":"4"},{"school_name":"西安建筑科技大學","school_id":"10"},{"school_name":"西安電子科技大學","school_id":"3"},{"school_name":"西安郵電大學","school_id":"1"},{"school_name":"長安大學","school_id":"9"},{"school_name":"陜西師范大學","school_id":"7"},{"school_name":"陜西科技大學","school_id":"11"}],"msg":"列表獲取成功","status":0}

用2個數組接收school_name和school_id

首先

public ? String[] schoolID;

public ?String[] schoolName;

JSONObject ?jsonObj_school；//用來接收解析的JSON字符串

JSONArray ?jsonArr_school ；//用來接收JSON對象里的數組

try{

jsonObj_school = new?JSONObject (?Value); //解析JSON字符串

jsonArr_school ?=jsonObj_school.getJSONArray("data");//接收JSON對象里的數組

int jsonSize_school = jsonArr_school.length();.//獲取數組長度

schoolID = new String[ jsonSize_school ];//初始化數組

schoolName = new String[ jsonSize_school];//初始化數組

for(int i = 0; i < jsonSize_school; i++ )//通過循環取出數組里的值

{

JSONObject jsonTemp = (JSONObject)jsonArr_school.getJSONObject(i);

schoolID[i] = jsonTemp.getString("school_id");

schoolName[i] = jsonTemp.getString("school_name");

}

}

catch(Exception e){

e.printStackTrace();

}

總結

以上是生活随笔為你收集整理的java解析json数组对象_JAVA中快速解析JSON对象里包含的JSON数组的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。