在?IntelliJ?IDEA?8.1中編寫一個ajax?jquery實例，取不到頁面上的值0

brnm12942014.08.17瀏覽115次分享舉報

public class AjaxServlet extends HttpServlet{

protected void doGet(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse)

throws ServletException, IOException {

doPost(httpServletRequest,httpServletResponse); //To change body of overridden methods use File | Settings | File Templates.

}

protected void doPost(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

try {

response.setContentType("text/html;charset=GB2312");

request.setCharacterEncoding("GB2312");

PrintWriter out = response.getWriter();

String oldname=null;

try {

oldname = request.getParameter("username");

System.out.println(oldname);

}catch(Exception e)

{e.getStackTrace();}

String password= request.getParameter("password");

if(oldname==null ||oldname.length()==0)

{ out.println("該用戶名不能為空值");}

else {

System.out.println("2222222");

String name=new String(oldname.getBytes("ISO8859-1"));

if(name.equals("amaker")){ System.out.println("*****");

out.println("該用戶名稱已存在!!");

}

else {

System.out.println("-------------");

out.println("驗證通過，你輸入的信息是:"+"["+name+"]"+"["+password+"]");

}

}

}

catch (Exception e)

{

System.out.println("異常");

}

}

}

verify.js

function verify()

{

alert("你點擊了按鈕，接下來來將執行驗證了!!!");

// 基于DOM技術 document.getElementById("userName");

//基于Jquery技術

// $("#userName")

var jqueryObj = $("#username");

var jqueryObj2 =$("#password");

var username= jqueryObj.val();

var password = jqueryObj2.val();

alert (username+": "+password);

$.get("servlet/AjaxServlet?name=" +username,null,callback);

//回調函數callback()

// 真正的驗證操作要在callback中做

function callback(data)

{

alert("服務器端的信息在這里返回!!");

alert(data);

var resultObj =$("#result");

resultObj.html(data);

alert("");

}

}

Validator.html:

/p>

"http://www.w3.org/TR/html4/loose.dtd">

hello,this is my first validateing html

用戶名稱:

用戶密碼:

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