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Pathfinding 模板题 /// BFS oj21413

發布時間:2023/12/8 编程问答 38 豆豆
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題目大意: Description

Bessie is stranded on a deserted arctic island and wants to determine all the paths she might take to return to her pasture. She has tested her boat and knows she can travel from one island to another island in 1 unit of time if a route with proper currents connects the pair.

She has experimented to create a map of the ocean with valid single-hop routes between each pair of the?N?(1 ≤?N?≤ 100) islands, conveniently numbered 1..N. The routes are one-way (unidirectional), owing to the way the currents push her boat in the ocean. It's possible that a pair of islands is connected by two routes that use different currents and thus provide a bidirectional connection. The map takes care to avoid specifying that a route exists between an island and itself.

Given her starting location?M?(1 ≤?M?≤?N) and a representation of the map, help Bessie determine which islands are one 'hop' away, two 'hops' away, and so on. If Bessie can take multiple different paths to an island, consider only the path with the shortest distance.

By way of example, below are?N=4 islands with connectivity as shown (for this example,?M=1):

start--> 1-------->2
? ? ? ? ?| ? ? ? ? |
? ? ? ? ?| ? ? ? ? |
? ? ? ? ?V ? ? ? ? V
? ? ? ? ?4<--------3

Bessie can visit island 1 in time 0 (since?M=1), islands 2 and 4 at time 1, and island 3 at time 2.

The input for this task is a matrix?C?where the element at row?r, column?c?is named?Crc?(0 ≤?Crc?≤ 1) and, if it has the value 1, means "Currents enable Bessie to travel directly from island?r?to island?c?in one time unit". Row?Cr?has?Nelements, respectively?Cr1..CrN, each one of which is 0 or 1.

Input

Multiple test cases. For each case:

* Line 1: ? Two space-separated integers:?N?and?M? ? ? ?

* Lines 2..N+1: ? Line?i+1 contains?N?space-separated integers:?Cr

Output

For each case, output lines 1..???: ? Line?i+1 contains the list of islands (in ascending numerical order) that Bessie can visit at time?i. ?Do not include any lines of output after all reachable islands have been listed.

Sample Input

4 1
0 1 0 1
0 0 1 0
0 0 0 1
0 0 0 0

Sample Output

1
2 4
3

?

其實就是一共N個點 從M出發?輸入樣例時已經把圖建好了

只不過這個圖是從1—N 而不是0—N-1罷了

直接遍歷輸出就行 注意末尾沒有空格?

#include <bits/stdc++.h> #define INF 0x3f3f3f3f using namespace std; int a[105][105],flag[105]; int main() {int n,m;while(~scanf("%d%d",&n,&m)){for(int i=1;i<=n;i++)for(int j=1;j<=n;j++)scanf("%d",&a[i][j]);memset(flag,INF,sizeof(flag));queue <int> q;q.push(m);flag[m]=0;while(!q.empty()){m=q.front(); q.pop();for(int i=1;i<=n;i++)if(a[m][i]==1&&flag[i]==INF){flag[i]=flag[m]+1;q.push(i);}}int sign=0;for(int i=0;i<n;i++){sign=0;for(int j=1;j<=n;j++)if(flag[j]==i){if(sign==0){printf("%d",j);sign=1;}else printf(" %d",j);}if(sign==1) printf("\n");}}return 0; } View Code

?

轉載于:https://www.cnblogs.com/zquzjx/p/8409060.html

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