歡迎進入Linux社區論壇，與200萬技術人員互動交流 >>進入 前提： 表一、 ddm_demand system_id demand_id quotate_end_team 1 1 team1,team5,team2 1 2 tea3,team1,team,4 pk:quotate_end_team、demand_id; 表二、 mc_team team_nam view_order team1 1 team

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前提：

表一、 ddm_demand

system_id demand_id quotate_end_team

1 1 team1,team5,team2

1 2 tea3,team1,team,4

pk:quotate_end_team、demand_id;

表二、 mc_team

team_nam view_order

team1 1

team2 2

解決問題：

將表一中的quotate_end_team字段按照表二的view_order重新排序。

方法：

DELIMITER $$

DROP PROCEDURE IF EXISTS order_team_name $$

CREATE PROCEDURE order_team_name()

BEGIN

declare order_before_teams text ;

declare temp_team_nam text;

declare systemId decimal(10,0) unsigned;

declare demandId char(6)；

declare done int;

-- 定義游標1

DECLARE rs_cursor CURSOR FOR SELECT system_id,demand_id,quotate_end_team FROM ddm_demand;

DECLARE CONTINUE HANDLER FOR NOT FOUND SET done=1;

open rs_cursor;

cursor_loop:loop

FETCH rs_cursor into systemId,demandId,order_before_teams;

if done=1 then

leave cursor_loop;

end if;

if order_before_teams is not null and order_before_teams <> '' then

SET @sqlstr = concat("where team_nam in ('",replace(order_before_teams,",","','")，"')；")；

SET @sqlstr = concat("CREATE VIEW temporary_team_view as SELECT team_nam,view_order FROM mc_team ",@sqlstr)；

-- DROP VIEW IF EXISTS temporary_team_view;

PREPARE stmt FROM @sqlstr;

EXECUTE stmt;

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