好吧,我想我已經(jīng)有了解決方案.這些數(shù)字與你的數(shù)字有點(diǎn)不同,但我相當(dāng)確定我的正在做你想要的.我們可以在第1步和第1步中完成所有工作. 2使用單個(gè)查詢(main_sql).必須使用遞歸語句(recur_sql)完成3和4.

with main_sql as (

select a.*,

b.*,

sum(a_amt) over (partition by b_id) as cd_amt,

rank() over (partition by a_cd order by b_id) as rnk

from (select a_cd, a_flag, sum(a_amt) as a_amt

from tablea

group by a_cd, a_flag) a,

tableb b

where a.a_flag = case when b.b_flag = 'Y' then a.a_flag else b.b_flag end

order by b_id, a_cd

),

recur_sql (a_cd, b_id, total_amt, cd_amt, resulting_ratio, resulting_amt, rnk) as (

select m.a_cd,

m.b_id,

m.a_amt as total_amt,

m.cd_amt, m.a_amt / m.cd_amt as resulting_ratio,

m.a_amt + (m.a_amt / m.cd_amt * m.b_amt) as resulting_amt,

rnk

from main_sql m

where rnk = 1

union all

select m.a_cd,

m.b_id,

r.resulting_amt as total_amt,

m.cd_amt,

r.resulting_amt / m.cd_amt as resulting_ratio,

r.resulting_amt + (r.resulting_amt / m.cd_amt * m.b_amt) as resulting_amt,

m.rnk

from recur_sql r,

main_sql m

where m.rnk > 1

and r.a_cd = m.a_cd

and m.rnk - 1 = r.rnk

)

select a_cd, b_id, total_amt, resulting_ratio, resulting_amt

from recur_sql

order by 2, 1

總結(jié)

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