Perishable Roads

智商題， 不會啊。。?

貼個官方題解

https://codeforces.com/blog/entry/51883

#include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ALL(x) (x).begin(), (x).end() #define fio ios::sync_with_stdio(false); cin.tie(0);using namespace std;const int N = 2000 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1e9 + 7; const double eps = 1e-8; const double PI = acos(-1);template<class T, class S> inline void add(T &a, S b) {a += b; if(a >= mod) a -= mod;} template<class T, class S> inline void sub(T &a, S b) {a -= b; if(a < 0) a += mod;} template<class T, class S> inline bool chkmax(T &a, S b) {return a < b ? a = b, true : false;} template<class T, class S> inline bool chkmin(T &a, S b) {return a > b ? a = b, true : false;}int n, mine = inf, G[N][N], d[N]; bool vis[N];int main() {scanf("%d", &n);for(int i = 1; i <= n; i++) {for(int j = i + 1; j <= n; j++) {scanf("%d", &G[i][j]);G[j][i] = G[i][j];chkmin(mine, G[i][j]);}}for(int i = 1; i <= n; i++) {for(int j = i + 1; j <= n; j++) {G[i][j] -= mine;G[j][i] -= mine;}}for(int i = 1; i <= n; i++) {d[i] = inf;for(int j = 1; j <= n; j++) {if(i != j) {chkmin(d[i], G[i][j] << 1);}}}d[0] = inf;for(int i = 1; i <= n; i++) {int p = 0;for(int j = 1; j <= n; j++) {if(!vis[j] && d[j] < d[p]) {p = j;}}for(int j = 1; j <= n; j++) {chkmin(d[j], d[p] + G[p][j]);}vis[p] = true;}for(int i = 1; i <= n; i++) printf("%lld\n", 1LL * (n - 1) * mine + d[i]);return 0; }/* */

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轉載于:https://www.cnblogs.com/CJLHY/p/11098059.html

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