日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

歡迎訪問 生活随笔!

生活随笔

當前位置: 首頁 > 人文社科 > 生活经验 >内容正文

生活经验

[Swift]LeetCode901. 股票价格跨度 | Online Stock Span

發布時間:2023/11/27 生活经验 35 豆豆
生活随笔 收集整理的這篇文章主要介紹了 [Swift]LeetCode901. 股票价格跨度 | Online Stock Span 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★
?微信公眾號:山青詠芝(shanqingyongzhi)
?博客園地址:山青詠芝(https://www.cnblogs.com/strengthen/)
?GitHub地址:https://github.com/strengthen/LeetCode
?原文地址:?https://www.cnblogs.com/strengthen/p/10607919.html?
?如果鏈接不是山青詠芝的博客園地址,則可能是爬取作者的文章。
?原文已修改更新!強烈建議點擊原文地址閱讀!支持作者!支持原創!
★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★★

Write a class?StockSpanner?which collects daily price quotes for some stock, and returns the?span?of that stock's price for the current day.

The span of the stock's price today?is defined as the maximum number of consecutive days (starting from today and going backwards)?for which the price of the stock was less than or equal to today's price.

For example, if the price of a stock over the next 7 days were?[100, 80, 60, 70, 60, 75, 85], then the stock spans would be?[1, 1, 1, 2, 1, 4, 6].?

Example 1:

Input: ["StockSpanner","next","next","next","next","next","next","next"], [[],[100],[80],[60],[70],[60],[75],[85]]
Output: [null,1,1,1,2,1,4,6]
Explanation: 
First, S = StockSpanner() is initialized.  Then:
S.next(100) is called and returns 1,
S.next(80) is called and returns 1,
S.next(60) is called and returns 1,
S.next(70) is called and returns 2,
S.next(60) is called and returns 1,
S.next(75) is called and returns 4,
S.next(85) is called and returns 6.Note that (for example) S.next(75) returned 4, because the last 4 prices
(including today's price of 75) were less than or equal to today's price.?

Note:

  1. Calls to?StockSpanner.next(int price)?will have?1 <= price <= 10^5.
  2. There will be at most?10000?calls to?StockSpanner.next?per test case.
  3. There will be at most?150000?calls to?StockSpanner.next?across all test cases.
  4. The total?time limit for this problem has been reduced by 75% for?C++, and 50% for all other languages.

編寫一個?StockSpanner?類,它收集某些股票的每日報價,并返回該股票當日價格的跨度。

今天股票價格的跨度被定義為股票價格小于或等于今天價格的最大連續日數(從今天開始往回數,包括今天)。

例如,如果未來7天股票的價格是?[100, 80, 60, 70, 60, 75, 85],那么股票跨度將是?[1, 1, 1, 2, 1, 4, 6]。?

示例:

輸入:["StockSpanner","next","next","next","next","next","next","next"], [[],[100],[80],[60],[70],[60],[75],[85]]
輸出:[null,1,1,1,2,1,4,6]
解釋:
首先,初始化 S = StockSpanner(),然后:
S.next(100) 被調用并返回 1,
S.next(80) 被調用并返回 1,
S.next(60) 被調用并返回 1,
S.next(70) 被調用并返回 2,
S.next(60) 被調用并返回 1,
S.next(75) 被調用并返回 4,
S.next(85) 被調用并返回 6。注意 (例如) S.next(75) 返回 4,因為截至今天的最后 4 個價格
(包括今天的價格 75) 小于或等于今天的價格。?

提示:

  1. 調用?StockSpanner.next(int price)?時,將有?1 <= price <= 10^5
  2. 每個測試用例最多可以調用??10000?次?StockSpanner.next
  3. 在所有測試用例中,最多調用?150000?次?StockSpanner.next
  4. 此問題的總時間限制減少了 50%。

Runtime:?840 ms Memory Usage:?23 MB
 1 class StockSpanner {
 2     var spans:[Int]
 3     var prices:[Int]
 4     var index:Int
 5 
 6     init() {
 7         spans = [Int](repeating:0,count:10_000)
 8         prices = [Int](repeating:0,count:10000)
 9         index = -1
10     }
11     
12     func next(_ price: Int) -> Int {
13         index += 1
14         prices[index] = price
15         if index == 0 || price < prices[index - 1]
16         {
17             spans[index] = 1
18             return 1
19         }
20         var previousIndex:Int = index - 1
21         var span:Int = 1
22         while (previousIndex >= 0 && price >= prices[previousIndex])
23         {
24             span += spans[previousIndex]
25             previousIndex -= spans[previousIndex]
26         }
27         spans[index] = span
28         return span
29     }
30 }
31 
32 /**
33  * Your StockSpanner object will be instantiated and called as such:
34  * let obj = StockSpanner()
35  * let ret_1: Int = obj.next(price)
36  */

892ms

 1 class StockSpanner {
 2 
 3     private var s = [(Int, Int)]()
 4     init() {
 5         
 6     }
 7     
 8     func next(_ price: Int) -> Int {
 9         var sum = 1
10         while !s.isEmpty, s.last!.0 <= price {
11             sum += s.removeLast().1
12         }
13         s.append((price, sum))
14         return sum
15     }
16 }

928ms

 1 class StockSpanner {
 2 
 3     init() {
 4         
 5     }
 6     
 7     struct PriceSpan {
 8         let price: Int
 9         let span: Int
10     }
11     
12     var stack = [PriceSpan]()
13     
14     func next(_ price: Int) -> Int {
15         guard stack.count > 0 else {
16             stack.append(PriceSpan(price: price, span: 1))
17             return 1
18         }
19         
20         var span = 1
21         while stack.last != nil && stack.last!.price <= price {
22             span += stack.last!.span
23             stack.removeLast()
24         }
25         
26         stack.append(PriceSpan(price: price, span: span))
27         return span
28     }
29 }
30 
31 /**
32  * Your StockSpanner object will be instantiated and called as such:
33  * let obj = StockSpanner()
34  * let ret_1: Int = obj.next(price)
35  */

1036ms

 1 class StockSpanner {
 2     private var span: [Int] = []
 3     private var stack: [StockSpan] = []
 4     init() {
 5         
 6     }
 7     
 8     func next(_ price: Int) -> Int {
 9         var stockSpan = StockSpan(price:price, span: 1)
10         while !stack.isEmpty && stack.last!.price <= stockSpan.price {
11             let removed = stack.removeLast()
12             stockSpan.span += removed.span
13         }
14         stack.append(stockSpan)
15         return stockSpan.span
16     }
17     
18     struct StockSpan {
19         let price: Int 
20         var span: Int
21     }
22 }
23 
24 /**
25  * Your StockSpanner object will be instantiated and called as such:
26  * let obj = StockSpanner()
27  * let ret_1: Int = obj.next(price)
28  */ 

 1 class StockSpanner {
 2     var prices: [Int] = []
 3     var days: [Int] = []
 4     init() {
 5         
 6     }
 7     
 8     func next(_ price: Int) -> Int {
 9         if prices.isEmpty || prices.last! > price {
10             prices.append(price)
11             days.append(1)
12             return 1
13         }
14         var index = prices.count - 1
15         var res = 1
16         while index >= 0 && prices[index] <= price {
17             res += days[index]
18             index -= days[index]
19         }
20         prices.append(price)
21         days.append(res)
22         return res
23     }
24 }
25 
26 /**
27  * Your StockSpanner object will be instantiated and called as such:
28  * let obj = StockSpanner()
29  * let ret_1: Int = obj.next(price)
30  */

 1 class StockSpanner {
 2     
 3     private var elements : [(price : Int, conquered : Int)] = []
 4     init() {
 5         
 6     }
 7     
 8     func next(_ price: Int) -> Int {
 9         var conquered : Int = 1
10         while !elements.isEmpty && elements.last!.price <= price {
11             let removed = elements.removeLast()
12             conquered += removed.conquered
13         }
14         
15         elements.append((price: price, conquered: conquered))
16         return elements.last!.conquered
17     }
18 }
19 
20 /**
21  * Your StockSpanner object will be instantiated and called as such:
22  * let obj = StockSpanner()
23  * let ret_1: Int = obj.next(price)
24  */

?

轉載于:https://www.cnblogs.com/strengthen/p/10607919.html

總結

以上是生活随笔為你收集整理的[Swift]LeetCode901. 股票价格跨度 | Online Stock Span的全部內容,希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯,歡迎將生活随笔推薦給好友。