方法是把數組中的數按2個2個的分成一組，先對比他們倆，然后再對比MAX和MIN。最后再加個判斷，如果是奇數，那最后一個數字也要和MAX和MIN判斷。

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using System; using System.Collections.Generic; using System.Linq; using System.Text;namespace ConsoleApplication4 {class Program{static void Main(string[] args){int[] input = { 1,2,-1,3,55,1};int max = 0;int min = 0;FindMaxAndMin(input, ref max, ref min);}static void FindMaxAndMin(int[] input, ref int max, ref int min){if (input==null||input.Length == 0){throw new Exception("input array can't be empty");}if (input.Length==1){throw new Exception("only on element in array, no max and min number");}max = input[0];min = input[0];int i = 0;for (; i +1 < input.Length; i= i+2){if (input[i]>input[i+1]){if (input[i]>max){max = input[i];}if (input[i+1]<min){min = input[i + 1];}}else{if (input[i]<min){min = input[i];}if (input[i+1]>max){max = input[i + 1];}}}if (i<input.Length){if (input[i]>max){max = input[i];}if (input[i]<min){min = input[i];}}Console.WriteLine("Max item is {0}, Min item is {1}",max,min);}} } View Code

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轉載于:https://www.cnblogs.com/Ligeance/p/3537762.html

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