C. Producing Snow
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Alice likes snow a lot! Unfortunately, this year’s winter is already over, and she can’t expect to have any more of it. Bob has thus bought her a gift — a large snow maker. He plans to make some amount of snow every day. On day i he will make a pile of snow of volume Vi and put it in her garden.

Each day, every pile will shrink a little due to melting. More precisely, when the temperature on a given day is Ti, each pile will reduce its volume by Ti. If this would reduce the volume of a pile to or below zero, it disappears forever. All snow piles are independent of each other.

Note that the pile made on day i already loses part of its volume on the same day. In an extreme case, this may mean that there are no piles left at the end of a particular day.

You are given the initial pile sizes and the temperature on each day. Determine the total volume of snow melted on each day.
Input

The first line contains a single integer N (1?≤?N?≤?105) — the number of days.

The second line contains N integers V1,?V2,?…,?VN (0?≤?Vi?≤?109), where Vi is the initial size of a snow pile made on the day i.

The third line contains N integers T1,?T2,?…,?TN (0?≤?Ti?≤?109), where Ti is the temperature on the day i.
Output

Output a single line with N integers, where the i-th integer represents the total volume of snow melted on day i.
Examples
Input
Copy

3
10 10 5
5 7 2

Output

5 12 4

Input
Copy

5
30 25 20 15 10
9 10 12 4 13

Output

9 20 35 11 25

Note

In the first sample, Bob first makes a snow pile of volume 10, which melts to the size of 5 on the same day. On the second day, he makes another pile of size 10. Since it is a bit warmer than the day before, the first pile disappears completely while the second pile shrinks to 3. At the end of the second day, he has only a single pile of size 3. On the third day he makes a smaller pile than usual, but as the temperature dropped too, both piles survive till the end of the day.

題解：對于每一個雪堆，沒有融化完時融化的都是t[i],我們只要確定這一天融化完的雪堆有幾個就好了，他們剩余的量就是a[i]-sum[i-1](sum[i-1]是之前的融化量，然后讓其余數量*t[i]就是當天的總融化量

#include <bits/stdc++.h> #define ll long long #define pb push_back #define inf 0x3f3f3f3f #define rep(i,a,b) for(int i=a;i<b;i++) #define rep1(i,a,b) for(int i=a;i>=b;i--) #define rson rt<<1|1,m+1,r #define lson rt<<1,l,m using namespace std; const int N=1e6+100; priority_queue<ll ,vector<ll>,greater<ll> >q; ll a[N],b[N],sum[N],t[N]; int main() {ll n;cin>>n;for(int i=1;i<=n;i++){cin>>a[i];}for(int i=1;i<=n;i++){cin>>t[i];sum[i]=t[i]+sum[i-1];}for(int i=1;i<=n;i++){long long ans=0;q.push(a[i]+sum[i-1]);while(!q.empty()&&q.top()<=sum[i]){ans+=q.top()-sum[i-1];q.pop();}ans+=q.size()*t[i];cout<<ans<<' ';}cout<<endl;return 0; }

轉載于:https://www.cnblogs.com/ffgcc/p/10546481.html

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