1124. Raffle for Weibo Followers (20)

時間限制 400 ms 內存限制 65536 kB 代碼長度限制 16000 B 判題程序 Standard 作者 CHEN, Yue

John got a full mark on PAT. He was so happy that he decided to hold a raffle（抽獎） for his followers on Weibo -- that is, he would select winners from every N followers who forwarded his post, and give away gifts. Now you are supposed to help him generate the list of winners.

Input Specification:

Each input file contains one test case. For each case, the first line gives three positive integers M (<= 1000), N and S, being the total number of forwards, the skip number of winners, and the index of the first winner (the indices start from 1). Then M lines follow, each gives the nickname (a nonempty string of no more than 20 characters, with no white space or return) of a follower who has forwarded John's post.

Note: it is possible that someone would forward more than once, but no one can win more than once. Hence if the current candidate of a winner has won before, we must skip him/her and consider the next one.

Output Specification:

For each case, print the list of winners in the same order as in the input, each nickname occupies a line. If there is no winner yet, print "Keep going..." instead.

Sample Input 1: 9 3 2 Imgonnawin! PickMe PickMeMeMeee LookHere Imgonnawin! TryAgainAgain TryAgainAgain Imgonnawin! TryAgainAgain Sample Output 1: PickMe Imgonnawin! TryAgainAgain Sample Input 2: 2 3 5 Imgonnawin! PickMe Sample Output 2: Keep going...

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對這道題的題意有些誤解，我以為是在抽到獎時看這個人是否得過獎，而實際上是每次疊加人數時，就要判斷這個人是否得過獎，得了獎就忽略。

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#include <bits/stdc++.h>using namespace std;int N, M, K; vector<string> userVec; vector<string> ansVec;int main() {cin>>N>>M>>K;string user;int m = 0;int k = 1;for(int i = 1; i <= N; i++) {cin>> user;//if(i >= K+m*M) {int flag = 1;for(int j = 0; j < ansVec.size(); j++) {if(user == ansVec[j]) {flag = 0;break;}}if(flag) {if(k >= K+m*M) {ansVec.push_back(user);m++;}k++;}//} }if(ansVec.empty()) {cout<< "Keep going..."<< endl;return 0;}for(int i = 0; i < ansVec.size(); i++) {cout<< ansVec[i]<< endl;}return 0; }

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轉載于:https://www.cnblogs.com/ACMessi/p/8527684.html

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