題目

Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to?m?+?n) to hold additional elements from B. The number of elements initialized in A and B are?m?and?nrespectively.

ps：下面的解法非常巧妙，我也沒想到，是借鑒leet里面某大神的代碼。

代碼

public class Solution {public void merge(int A[], int m, int B[], int n) {while (m > 0 && n > 0) {if (A[m-1] > B[n-1]) {A[m+n-1] = A[m-1];m--;} else {A[m+n-1] = B[n-1];n--;}}while (n > 0) {A[n-1] = B[n-1];n--;}} }


代碼下載：https://github.com/jimenbian/GarvinLeetCode

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