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关于Java中try-catch-finally-return的执行顺序

發布時間:2025/3/21 java 31 豆豆
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1、try塊中沒有拋出異常,try、catch和finally塊中都有return語句

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 public?static?int?NoException(){ ?????????int?i=10; ?????????try{ ???????????System.out.println("i in try block is:"+i); ???????????return?--i; ?????????} ?????????catch(Exception e){ ???????????--i; ???????????System.out.println("i in catch - form try block is:"+i); ???????????return?--i; ?????????} ?????????finally{????? ???????????System.out.println("i in finally - from try or catch block is:"+i); ???????????return?--i; ?????????}?? }

運行代碼:

1 2 3 4 5 public?static?void?main(String[] args) { ????????System.out.println("=============NoException=================="); ????????System.out.println(NoException()); ????????System.out.println("===============================");??? }

運行結果:

1 2 3 4 5 =============NoException================== i?in?try?block?is:10 i?in?finally?- from?try?or?catch?block?is:9 8 ===============================


執行順序:

? ?執行try塊,執行到return語句時,先執行return的語句,--i,但是不返回到main方法,執行finally塊,遇到finally塊中的return語句,執行--i,并將值返回到main方法,這里就不會再回去返回try塊中計算得到的值。

結論:try-catch-finally都有return語句時,沒有異常時,返回值是finally中的return返回的。


2.try塊中沒有拋出異常,僅try和catch中有return語句

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 public?static?int?NoException1(){ ????????????int?i=10; ????????????try{ ????????????????System.out.println("i in try block is:"+i); ????????????????return?--i; ????????????} ????????????catch(Exception e){ ????????????????--i; ????????????????System.out.println("i in catch - form try block is:"+i); ????????????????return?--i; ????????????} ????????????finally{??????????? ????????????????System.out.println("i in finally - from try or catch block is:"+i); ????????????????--i; ????????????????System.out.println("i in finally block is:"+i); ????????????????//return --i; ????????????} }

運行結果:

1 2 3 4 5 6 =============NoException1================== i?in?try?block?is:10 i?in?finally?- from?try?or?catch?block?is:9 i?in?finally?block?is:8 9 ===============================

執行順序:

? ?try中執行完return的語句后,不返回,執行finally塊,finally塊執行結束后,返回到try塊中,返回i在try塊中最后的值。

結論:try-catch都有return語句時,沒有異常時,返回值是try中的return返回的。


3.try塊中拋出異常,try、catch和finally中都有return語句

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 public?static?int?WithException(){ ????????????int?i=10; ????????????try{ ????????????????System.out.println("i in try block is:"+i); ????????????????i = i/0; ????????????????return?--i; ????????????} ????????????catch(Exception e){ ????????????????System.out.println("i in catch - form try block is:"+i); ????????????????--i; ????????????????System.out.println("i in catch block is:"+i); ????????????????return?--i; ????????????} ????????????finally{??????????? ????????????????System.out.println("i in finally - from try or catch block is--"+i); ????????????????--i; ????????????????System.out.println("i in finally block is--"+i); ????????????????return?--i; ????????????} }

執行結果:

1 2 3 4 5 6 7 8 =============WithException================== i?in?try?block?is:10 i?in?catch?- form?try?block?is:10 i?in?catch?block?is:9 i?in?finally?- from?try?or?catch?block?is--8 i?in?finally?block?is--7 6 ===============================

執行順序:

? ?拋出異常后,執行catch塊,在catch塊的return的--i執行完后,并不直接返回而是執行finally,因finally中有return語句,所以,執行,返回結果6。

結論:

? ?try塊中拋出異常,try、catch和finally中都有return語句,返回值是finally中的return。


4.try塊中拋出異常,try和catch中都有return語句

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public?static?int?WithException1(){ ????????????int?i=10; ????????????try{ ????????????????System.out.println("i in try block is:"+i); ????????????????i=i/0; ????????????????return?--i; ????????????}catch(Exception e){ ????????????????System.out.println("i in catch - form try block is:"+i);??????????? ????????????????return?--i; ????????????}finally{ ?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? ????????????????System.out.println("i in finally - from try or catch block is:"+i); ????????????????--i; ????????????????System.out.println("i in finally block is:"+i); ????????????????//return i; ????????????} }

執行結果:

1 2 3 4 5 6 7 =============WithException1================== i?in?try?block?is:10 i?in?catch?- form?try?block?is:10 i?in?finally?- from?try?or?catch?block?is:9 i?in?finally?block?is:8 9 ===============================

執行順序:

? ?拋出異常后,執行catch塊,執行完finally語句后,依舊返回catch中的執行return語句后的值,而不是finally中修改的值。

結論:

? ?返回的catch中return值。


5.try、catch中都出現異常,在finally中有返回

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 public?static?int?WithException2(){ ????????????int?i=10; ????????????try{ ????????????????System.out.println("i in try block is:"+i); ????????????????i=i/0; ????????????????return?--i; ????????????} ????????????catch(Exception e){ ????????????????System.out.println("i in catch - form try block is:"+i); ????????????????int?j = i/0; ????????????????return?--i; ????????????} ????????????finally{ ??????????????????????????????????????????????????????????????????????????????????????? ????????????????System.out.println("i in finally - from try or catch block is:"+i); ????????????????--i; ????????????????--i; ????????????????System.out.println("i in finally block is:"+i); ????????????????return?--i; }

執行結果:

1 2 3 4 5 6 7 =============WithException2================== i?in?try block?is:10 i?in?catch - form try block?is:10 i?in?finally -?from?try?or?catch block?is:10 i?in?finally block?is:8 7 ===============================

執行順序: ??

? ?try塊中出現異常到catch,catch中出現異常到finally,finally中執行到return語句返回,不檢查異常。

結論:

? ?返回finally中return值。


6、只在函數最后出現return語句

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 public?static?int?WithException3(){ ????????????int?i=10; ????????????try{ ????????????????System.out.println("i in try block is:"+i); ????????????????i=i/0; ????????????????//return --i; ????????????} ????????????catch(Exception e){ ????????????????System.out.println("i in catch - form try block is:"+i); ????????????????//int j = i/0; ????????????????//return --i; ????????????} ????????????finally{ ?????????????????????????????????????????????????????????????????????????? ????????????????System.out.println("i in finally - from try or catch block is:"+i); ????????????????--i; ????????????????--i; ????????????????System.out.println("i in finally block is:"+i); ????????????????//return --i; ????????????} ????????????return?--i; }

執行結果:

1 2 3 4 5 6 7 =============WithException3================== i?in?try?block?is:10 i?in?catch?- form?try?block?is:10 i?in?finally?- from?try?or?catch?block?is:10 i?in?finally?block?is:8 7 ===============================


總體結論:

結論一:

? ?return語句并不是函數的最終出口,如果有finally語句,這在return之后還會執行finally(return的值會暫存在棧里面,等待finally執行后再返回)
結論二:

? ?finally里面不建議放return語句,根據需要,return語句可以放在try和catch里面和函數的最后。可行的做法有四:
? ?(1)return語句只在函數最后出現一次
? ?(2)return語句僅在try和catch里面都出現。
? ?(3)return語句僅在try和函數的最后都出現。
? ?(4)return語句僅在catch和函數的最后都出現。
? ?注意,除此之外的其他做法都是不可行的,編譯器會報錯。


from:?http://qing0991.blog.51cto.com/1640542/1387200

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