日韩性视频-久久久蜜桃-www中文字幕-在线中文字幕av-亚洲欧美一区二区三区四区-撸久久-香蕉视频一区-久久无码精品丰满人妻-国产高潮av-激情福利社-日韩av网址大全-国产精品久久999-日本五十路在线-性欧美在线-久久99精品波多结衣一区-男女午夜免费视频-黑人极品ⅴideos精品欧美棵-人人妻人人澡人人爽精品欧美一区-日韩一区在线看-欧美a级在线免费观看

    歡迎訪問 生活随笔!

    生活随笔

    當前位置: 首頁 > 编程资源 > 编程问答 >内容正文

    编程问答

    Codeforces Round #555 (Div. 3) c2 d e f

    發布時間:2025/3/21 编程问答 26 豆豆
    生活随笔 收集整理的這篇文章主要介紹了 Codeforces Round #555 (Div. 3) c2 d e f 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

    c2:Increasing Subsequence (hard version)

    那邊小取那邊,然后相等比較后面的長度

    #include<bits/stdc++.h> using namespace std; #define maxn 500005 int a[maxn]; int main(){int n,mx=0,in;scanf("%d",&n);for(int j=0;j<n;j++){scanf("%d",&a[j]);if(mx<a[j]){mx = a[j];in = j;}}string s="";int l = 0,r = n-1,k=-1;while(l<=r){if(k<min(a[l],a[r])){if(a[l]<a[r]){s+="L";k=a[l];l++;}else if(a[l]>a[r]){s+='R';k=a[r];r--;}else{int res1=0,x=k;int res2=0,y=k;for(int i = l;i<=in;i++){if(a[i]>x){x = a[i];res1++;}else break;}for(int i = r;i>=in;i--){if(a[i]>y){y = a[i];res2++;}else break;}if(res1>res2){k = a[l];l++;s+='L';}else{k = a[r];r--;s+='R';}}}else if(k<a[l]){s+='L';k = a[l];l++;}else if(k<a[r]){s+='R';k = a[r];r--;}else break;}cout<<s.size()<<endl;cout<<s<<endl; }

    ?

    D:N Problems During K Days

    ?

    #include<bits/stdc++.h> using namespace std; #define maxn 500005 #define LL long long LL a[maxn]; int main(){LL n,m;scanf("%lld%lld",&n,&m);for(int j=0;j<m;j++){a[j] = (n - (m - j) * (m - 1 -j) / 2) / (m-j);//cout<<a[j]<<endl;if(j>0&&a[j]>a[j-1]*2){a[j]=a[j-1]*2;}n-=a[j];if(n<0){cout<<"NO"<<endl;return 0;}}if(n){cout<<"NO"<<endl;return 0;}cout<<"YES"<<endl;for(int j=0;j<m;j++){cout<<a[j]<<" ";} }

    ?

    E:Minimum Array

    #include<bits/stdc++.h> using namespace std; #define maxn 500005 #define LL long long int a[maxn]; map<int,int>mp; set<int>s; vector<int>Q; int main(){int n;cin>>n;for(int j=0;j<n;j++){cin>>a[j];}for(int j=0;j<n;j++){int x;cin>>x;mp[x]++;s.insert(x);}for(int j=0;j<n;j++){int x = (n-a[j])%n;set<int> ::iterator it = s.lower_bound(x);if(it==s.end()){it=s.begin();}if(mp[*it]>0){mp[*it]--;cout<<(*it+a[j])%n<<" ";}if(mp[*it]==0){s.erase(it);}} }

    ?

    F:Maximum Balanced Circle

    #include<bits/stdc++.h> using namespace std; #define maxn 500005 #define LL long long int a[maxn]; map<int,int>mp; set<int>s; vector<int>q,w; int main(){int n;cin>>n;for(int j=0;j<n;j++){scanf("%d",&a[j]);mp[a[j]]++;q.push_back(a[j]);}sort(q.begin(),q.end());q.erase(unique(q.begin(),q.end()),q.end());int l =0,mx = 0,res = 0,r=-1;for(int j=0;j<q.size();j++){if(res==0){res+=mp[q[j]];if(res>mx){mx = res;r = j;}}else{if(q[j]==q[j-1]+1){if(mp[q[j]]>=2){res+=mp[q[j]];if(res>mx){mx = res;r = j;}}else{res+=mp[q[j]];if(res>mx){mx = res;r = j;}res = mp[q[j]];}}else{res=mp[q[j]];if(res>mx){mx = res;r = j;}}}} // if(mx==21){ // cout<<q[r]<<endl; // } // cout<<mx<<" "<<r<<endl;int s = mp[q[r]];for(int j=r-1;j>=0;j--){if(q[j]+1!=q[j+1]){l=j+1;break;}else{s+=mp[q[j]];if(s==mx){l=j;break;}}} // cout<<l<<endl;for(int j=l;j<=r;j++){while(mp[q[j]]>1){w.push_back(q[j]);mp[q[j]]--;}}for(int j=r;j>=l;j--){w.push_back(q[j]);}cout<<w.size()<<endl;for(int j=0;j<w.size();j++){cout<<w[j]<<" ";} }

    ?

    ?

    轉載于:https://www.cnblogs.com/DyLoder/p/10794457.html

    總結

    以上是生活随笔為你收集整理的Codeforces Round #555 (Div. 3) c2 d e f的全部內容,希望文章能夠幫你解決所遇到的問題。

    如果覺得生活随笔網站內容還不錯,歡迎將生活随笔推薦給好友。