系統中有一個表中，人員存放的是多個
并且，存放的不是姓名，而是code，code之間使用逗號分隔

頁面，需要顯示所有人員的姓名
把數組中的code，作為key放在map中，獲取每一個員工姓名

@RequestMapping(method = RequestMethod.GET) public String list(Page<SamplePreparationInfoExt> page, Model model, @RequestParam Map<String, String> param) {List<PersonInfoExt> personInfoList = this.personInfoExtService.selectPersonByDeptId(currentUser != null ? currentUser.getDepartmentCode() : null);List<SamplePreparationInfoExt> SamplePreparationInfoExtList = samplePreparationWebService.selectExtListByMap(page, param);for (int i = 0; i < SamplePreparationInfoExtList.size(); i++) {String opertor = SamplePreparationInfoExtList.get(i).getLabSampleAcceptor();String opertorName = "";if (opertor == null || opertor.equals("")) {SamplePreparationInfoExtList.get(i).setLabSampleAcceptor(opertorName);} else {int number = StringUtils.countMatches(opertor, ",");Map<String, String> nameMap = new HashMap<>();for (int j = 0; j < number + 1; j++) {String opertorCode = "";opertorCode = opertor.substring(j * 8 + j, (j + 1) * 8 + j);nameMap.put(opertorCode, "");}if (nameMap.size() == 0) {SamplePreparationInfoExtList.get(i).setLabSampleAcceptor(opertorName);} else {int k = 0;for (String key : nameMap.keySet()) {// 獲取名字String name = getOpertorNameByCode(personInfoList, key);if (k == 0) {opertorName = name;} else {opertorName = opertorName + ',' + name;}k = k + 1;}SamplePreparationInfoExtList.get(i).setLabSampleAcceptor(opertorName);}}}setCommonData(model);page.setResult(SamplePreparationInfoExtList);model.addAttribute("page", page);return this.viewName("list"); }// 獲取化驗員姓名 public String getOpertorNameByCode(List<PersonInfoExt> personInfoList, String opertorCode) {String opertorName = "";for (int i = 0; i < personInfoList.size(); i++) {if (opertorCode != null) {if (opertorCode.equals(personInfoList.get(i).getCode())) {opertorName = personInfoList.get(i).getName();}}}return opertorName; }

注意
使用substring截取String，必須保證這個code的位數，必須是固定的

考慮到性能，只有list在不大的情況下，才可以使用
或者盡量過濾list集合中的數據，減少遍歷次數

總結

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