要求：解析下面JSON數據

String string = “{no:1,name:’Android’,employees:[{name:’zhangsan’,age:20},{name:’lisi’,age:21},{name:’wangwu’,age:22}]}”;

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代碼：

package com.qf.demo4;import java.util.ArrayList;import com.alibaba.fastjson.JSON;public class Test {public static void main(String[] args) {//fastjson解析數據//1.阿里解析過程和Gson類似，String string= "{no:1,name:'android',employees:[{name:'zhangsan',age:20},{name:'lisi',age:21},{name:'wangwu',age:22}]}";Employ employ = JSON.parseObject(string,Employ.class);System.out.println(employ);} }class Person{private String name;private int age;public Person(String name, int age) {super();this.name = name;this.age = age;}public Person() {super();}public String getName() {return name;}public void setName(String name) {this.name = name;}public int getAge() {return age;}public void setAge(int age) {this.age = age;}@Overridepublic String toString() {return "Person [name=" + name + ", age=" + age + "]";}}class Employ{private int no;private String name;private ArrayList<Person> employees;public Employ(int no, String name, ArrayList<Person> employees) {super();this.no = no;this.name = name;this.employees = employees;}public Employ() {super();}public int getNo() {return no;}public void setNo(int no) {this.no = no;}public String getName() {return name;}public void setName(String name) {this.name = name;}public ArrayList<Person> getEmployees() {return employees;}public void setEmployees(ArrayList<Person> employees) {this.employees = employees;}@Overridepublic String toString() {return "Employ [no=" + no + ", name=" + name + ", employees=" + employees + "]";}} 《新程序員》：云原生和全面數字化實踐50位技術專家共同創作，文字、視頻、音頻交互閱讀

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