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發布時間:2025/3/20 编程问答 20 豆豆
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writen by wqj1212@yahoo.com.cn

思路
1.先對圖像標記。給每個目標一個標號。
2.然后計算每個被標號目標的NMI特征值,
3.然后這些NMI特征值與已知要識別目標NMI特征值比較。
如果差值小于某個閾值,就說明該目標就是要識別的目標。

BOOL?Cbiaoji1::ObjectionExtrationNMI(IplImage?*src)
{
????DWORD?t3,t4;
bool?status=false;
????t3
=::GetTickCount();
????IplImage?
*imgOb=NULL;
????IplImage?
*obImageNMI[255];
????
float?M[255];
????
float?J[255];
????
float?cx[255];
????
float?cy[255];
????
for(int?i=0;i<255;i++)
????
{
????????M[i]
=0.0;
????????J[i]
=0.0;
????????cx[i]
=0.0;
????????cy[i]
=0.0;
????obImageNMI[i]
=cvCreateImage(cvSize(src->width,src->height),8,1);
????cvZero(obImageNMI[i]);
????}

????imgOb
=cvCreateImage(cvSize(src->width,src->height),8,1);
cvZero(imgOb);
????????
biaoji(src);
????
for(int?t=0;t<=x_sign;t++)
????
{
????????
if(flag[t]>0)
????????
{
????????????
for(int?m=0;m<src->height;m++)
????????????
for(int?n=0;n<src->width;n++)
????????????
{
????????????????
if(CV_IMAGE_ELEM(temp,uchar,m,n)==t)
????????????????
{
????????????????????CV_IMAGE_ELEM(obImageNMI[t],uchar,m,n)
=255;
????????????????}

????????????}

????????????
for(int?j=0;j<src->height;j++)
????
????????
for(i=0;i<src->width;i++)
????????
{

????????????
????????????M[t]
+=(int)CV_IMAGE_ELEM(obImageNMI[t],uchar,j,i?);
????????????cx[t]
+=j*(int)CV_IMAGE_ELEM(obImageNMI[t],uchar,j,i);
????????????cy[t]
+=i*(int)CV_IMAGE_ELEM(obImageNMI[t],uchar,j,i);
????
????????????
????????}

????????
????????????
?????cx[t]
/=M[t];
?????cy[t]
/=M[t];

?????
for(j=0;j<src->height;j++)
?????????
for(?i=0;i<src->width;i++)
?????????
{
?????????????J[t]
+=((j-cx[t])*(j-cx[t])+(i-cy[t])*(i-cy[t]))*(int)(CV_IMAGE_ELEM(obImageNMI[t],uchar,j,i));
?????????????
?????????}

????J[t]
=sqrt(J[t])/M[t];
????????}

????}

????
for(t=0;t<=x_sign;t++)
????
{
????????
if(J[t]!=0)
????????
{????????cout<<"連通區"<<t<<"的NMI特征值"<<J[t]<<endl;
????????
if((fabs(J[t]-ModelNMIFeature)/J[t])<=1-PiPei/100)
????????
{
?????????
for(int?m=0;m<src->height;m++)
????????????
for(int?n=0;n<src->width;n++)
????????????
{
????????????????
if(CV_IMAGE_ELEM(temp,uchar,m,n)==t)
????????????????????CV_IMAGE_ELEM(imgOb,uchar,m,n)
=255;
??????????status
=true;
????????????}

????????
????????}
}

????
????}

????
for(?i=0;i<255;i++)
????
{
????
cvReleaseImage(
&obImageNMI[i]);
????
????}

????cvCopy(imgOb,src);
????????cvReleaseImage(
&imgOb);
????????????cvReleaseImage(
&temp);
????????????t4
=::GetTickCount();
????????????cout
<<"t4-t3="<<t4-t3<<endl;
????????????
if(status)
????????????
return?true;
????????????
else
????????????????
return?false;
}

轉載于:https://www.cnblogs.com/wqj1212/archive/2007/12/21/1009665.html

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