python中locals函数_Python locals()函数
# Python `locals()`函數(shù)
> 原文： [https://thepythonguru.com/python-builtin-functions/locals/](https://thepythonguru.com/python-builtin-functions/locals/)
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于 2020 年 1 月 7 日更新
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`locals()`函數(shù)返回一個(gè)字典，其中包含在本地名稱空間中定義的變量。 在全局名稱空間中調(diào)用`locals()`與調(diào)用[`globals()`](/python-builtin-functions/globals/)相同，并返回代表模塊全局名稱空間的字典。
其語法如下：
```py
locals() -> dictionary containg local scope variables
```
這是一個(gè)例子：
```py
#!/usr/bin/python3
from pprint import pprint
a = 10
b = 20
def foo():
x = 30 # x and y are local variables
y = 40
print("locals() = {0}".format(locals()))
pprint(locals()) # same as calling globals()
print('*' * 80)
print("locals() == globals()? ", locals() == globals())
print('*' * 80)
foo()
```
**預(yù)期輸出**：
```py
{'__builtins__': ,
'__cached__': None,
'__doc__': None,
'__file__': 'module1.py',
'__loader__': <_frozen_importlib_external.sourcefileloader object at>,
'__name__': '__main__',
'__package__': None,
'__spec__': None,
'a': 10,
'b': 20,
'foo': ,
'pprint': }
********************************************************************************
locals() == globals()? True
********************************************************************************
locals() = {'y': 40, 'x': 30}
```
試試看：
```py
from pprint import pprint
a = 10
b = 20
def foo():
x = 30 # x and y are local variables
y = 40
print("locals() = {0}".format(locals()))
pprint(locals()) # same as calling globals()
print('*' * 80)
print("locals() == globals()? ", locals() == globals())
print('*' * 80)
foo()
```
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