這些在語法上有錯誤
[root@centos home]# ./03.sh
這個程序旨在幫助你知道你的退伍日期（例如20100909)
輸入你的退伍日期==>:20100909
./03.sh: line 15: declare: date +%s: syntax error: operand expected
(error token is "%s")
./03.sh: line 16: declare: date --date="$some" +%s: syntax error in
expression (error token is "date="$some" +%s")
./03.sh: line 17: declare: $(($some_time-$now_time)): syntax error:
operand expected (error token is "$(($some_time-$now_time))")
./03.sh: line 18: declare: $(($my_s/60/60/24)): syntax error: operand
expected (error token is "$(($my_s/60/60/24))")
./03.sh: line 20: [: -lt: unary operator expected
目前你離退伍還有天
____________________________________________________________
附上我的系統(tǒng)版本：
[root@centos home]# uname -a
Linux centos 2.6.18-194.el5 #1 SMP Fri Apr 2 14:58:35 EDT 2010 i686 i686
i386 GNU/Linux

附上我的腳本內(nèi)容。
#!/bin/bash
#this is a test script
#made by chenbaocheng?? ctime:2010/8/25
PATH=/bin:/sbin:/usr/bin:/usr/sbin:/usr/local/bin:/usr/local/sbin/:~/bin
export PATH

echo "這個程序旨在幫助你知道你的退伍日期（例如20100909) "
read -p "輸入你的退伍日期==>:" some
test -z "$some" && echo "不輸名字是不行的" && exit 0
some2='echo $some | grep '[0-9]\{8\}''
if? [ "$some2" = "" ]; then
????????echo "你的輸入有問題，請重新再來"
fi
declare -i now_time='date +%s'
declare -i some_time='date --date="$some" +%s'
declare -i my_s='$(($some_time-$now_time))'
declare -i my_day='$(($my_s/60/60/24))'

if ["$my_day" -lt "0" ];then
????????echo "你已經(jīng)退伍有"$((-1*$my_day))"了，屬于老革命了"
else
????????echo "目前你離退伍還有$my_day天"
fi
?

轉(zhuǎn)載于:https://blog.51cto.com/myhat/382811

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