遍历二位数组的方法
NowMapInfo為一個in[39,13]的二維數組
NowMapInfo.GetLength(0);
取該數組第一維的長度,也就是39
NowMapInfo.GetLength(1);
取該數組第二維的長度,也就是13
?
for (int i = 0; i < NowMapInfo.GetLength(0); i++)
??????????????????? {
??????????????????????? for (int j = 0; j < NowMapInfo.GetLength(1); j++)
??????????????????????? {
??????????????????????????? if (NowMapInfo[i, j] != 0 && NowMapInfo[i, j] != 3)
??????????????????????????? {
??????????????????????????????? mapDigSum++;
??????????????????????????? }
??????????????????????? }
??????????????????? }
轉載于:https://www.cnblogs.com/kingfly/archive/2010/02/08/1665873.html
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