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Java中List的排序

發布時間:2025/3/15 java 27 豆豆
生活随笔 收集整理的這篇文章主要介紹了 Java中List的排序 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.

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第一種方法,就是list中對象實現Comparable接口,代碼如下:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 public? class? Person? implements? Comparable<Person> { ???? private? String name; ???? private? Integer order; ???? /** ????? * @return the name ????? */ ???? public? String getName() { ???????? return? name; ???? } ???? /** ????? * @param name ????? *??????????? the name to set ????? */ ???? public? void? setName(String name) { ???????? this .name = name; ???? } ???? /** ????? * @return the order ????? */ ???? public? Integer getOrder() { ???????? return? order; ???? } ???? /** ????? * @param order ????? *??????????? the order to set ????? */ ???? public? void? setOrder(Integer order) { ???????? this .order = order; ???? } ???? @Override ???? public? int? compareTo(Person arg0) { ???????? return? this .getOrder().compareTo(arg0.getOrder()); ???? } }


1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 public? static? void? main(String[] args) { ???? List<Person> listA =? new? ArrayList<Person>(); ???? Person p1 =? new? Person(); ???? Person p2 =? new? Person(); ???? Person p3 =? new? Person(); ???? p1.setName( "name1" ); ???? p1.setOrder( 1 ); ???? p2.setName( "name2" ); ???? p2.setOrder( 2 ); ???? p3.setName( "name3" ); ???? p3.setOrder( 3 ); ???? listA.add(p2); ???? listA.add(p1); ???? listA.add(p3); ???? Collections.sort(listA); ???? for? (Person p : listA) { ???????? System.out.println(p.getName()); ???? } }


第二種方法,就是在重載Collections.sort方法,代碼如下:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 public? class? Person { ???? private? String name; ???? private? Integer order; ???? /** ????? * @return the name ????? */ ???? public? String getName() { ???????? return? name; ???? } ???? /** ????? * @param name ????? *??????????? the name to set ????? */ ???? public? void? setName(String name) { ???????? this .name = name; ???? } ???? /** ????? * @return the order ????? */ ???? public? Integer getOrder() { ???????? return? order; ???? } ???? /** ????? * @param order ????? *??????????? the order to set ????? */ ???? public? void? setOrder(Integer order) { ???????? this .order = order; ???? } }


1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 public? static? void? main(String[] args) { ???????? List<Person> listA =? new? ArrayList<Person>(); ???????? Person p1 =? new? Person(); ???????? Person p2 =? new? Person(); ???????? Person p3 =? new? Person(); ???????? p1.setName( "name1" ); ???????? p1.setOrder( 1 ); ???????? p2.setName( "name2" ); ???????? p2.setOrder( 2 ); ???????? p3.setName( "name3" ); ???????? p3.setOrder( 3 ); ???????? listA.add(p2); ???????? listA.add(p1); ???????? listA.add(p3); ????????? ???????? Collections.sort(listA,? new? Comparator<Person>() { ???????????? public? int? compare(Person arg0, Person arg1) { ???????????????? return? arg0.getOrder().compareTo(arg1.getOrder()); ???????????? } ???????? }); ????????? ???????? for? (Person p : listA) { ???????????? System.out.println(p.getName()); ???????? } ???? }


轉載于:https://my.oschina.net/u/1177694/blog/508053

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