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?微信公眾號：山青詠芝（shanqingyongzhi）
?博客園地址：山青詠芝（https://www.cnblogs.com/strengthen/）
?GitHub地址：https://github.com/strengthen/LeetCode
?原文地址：?https://www.cnblogs.com/strengthen/p/10543038.html?
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In a forest, each rabbit has some color. Some subset of rabbits (possibly all of them) tell you how many other rabbits have the same color as them. Those?answers?are placed in an array.

Return the minimum number of rabbits that could be in the forest.

Examples: Input: answers = [1, 1, 2] Output: 5 Explanation: The two rabbits that answered "1" could both be the same color, say red. The rabbit than answered "2" can't be red or the answers would be inconsistent. Say the rabbit that answered "2" was blue. Then there should be 2 other blue rabbits in the forest that didn't answer into the array. The smallest possible number of rabbits in the forest is therefore 5: 3 that answered plus 2 that didn't.Input: answers = [10, 10, 10] Output: 11Input: answers = [] Output: 0

Note:

answers?will have length at most?1000.

Each?answers[i]?will be an integer in the range?[0, 999].

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森林中，每個兔子都有顏色。其中一些兔子（可能是全部）告訴你還有多少其他的兔子和自己有相同的顏色。我們將這些回答放在?answers?數組里。

返回森林中兔子的最少數量。

示例: 輸入: answers = [1, 1, 2] 輸出: 5 解釋: 兩只回答了 "1" 的兔子可能有相同的顏色，設為紅色。 之后回答了 "2" 的兔子不會是紅色，否則他們的回答會相互矛盾。 設回答了 "2" 的兔子為藍色。 此外，森林中還應有另外 2 只藍色兔子的回答沒有包含在數組中。 因此森林中兔子的最少數量是 5: 3 只回答的和 2 只沒有回答的。輸入: answers = [10, 10, 10] 輸出: 11輸入: answers = [] 輸出: 0

說明:

answers?的長度最大為1000。

answers[i]?是在?[0, 999]?范圍內的整數。

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Runtime:?20 ms Memory Usage:?19.3 MB 1 class Solution { 2 func numRabbits(_ answers: [Int]) -> Int { 3 var res:Int = 0 4 var m:[Int:Int] = [Int:Int]() 5 for ans in answers 6 { 7 m[ans,default:0] += 1 8 } 9 for (key,val) in m 10 { 11 res += (val + key) / (key + 1) * (key + 1) 12 } 13 return res 14 } 15 }

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24ms

1 class Solution { 2 func numRabbits(_ answers: [Int]) -> Int { 3 var counter = [Int: Int]() 4 answers.forEach{ counter[$0, default: 0] += 1 } 5 6 var ret = 0 7 for (n, c) in counter { 8 let colors = (c + n) / (n + 1) 9 ret += colors * (n + 1) 10 } 11 return ret 12 } 13 }

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24ms

1 class Solution { 2 func numRabbits(_ answers: [Int]) -> Int { 3 if answers.count == 0 { 4 return 0 5 } 6 7 let sortAns = answers.sorted() 8 var first = -1 9 10 var total = 0 11 var sep = 0 12 13 for (_, itemCount) in sortAns.enumerated() { 14 if itemCount != first || sep == first { 15 first = itemCount 16 sep = 0 17 18 total += 1 + itemCount 19 } else { 20 sep += 1 21 } 22 } 23 return total 24 } 25 }

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48ms

1 class Solution { 2 func numRabbits(_ answers: [Int]) -> Int { 3 var mark = [Int : Int]() 4 for answer in answers { 5 if let count = mark[answer] { 6 mark[answer] = count + 1 7 } else { 8 mark[answer] = 1 9 } 10 } 11 12 var result = 0 13 for (key, value) in mark { 14 let groupNum = key + 1 15 var group = value / groupNum 16 if value % groupNum != 0 { 17 group += 1 18 } 19 result += group * groupNum 20 } 21 return result 22 } 23 }

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轉載于:https://www.cnblogs.com/strengthen/p/10543038.html

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