LinkedList公共int indexOf(Object o)方法 (LinkedList public int indexOf(Object o) method)

• This method is available in package java.util.LinkedList.indexOf(Object o).

  軟件包java.util.LinkedList.indexOf(Object o)中提供了此方法。

• This method is used to return the position or index of the first occurrence of the specified object of the linked list.

  此方法用于返回鏈表中指定對象首次出現的位置或索引。

• In this method it returns -1 in two cases first will be if the element doesn't exist in the list then it returns -1 and second will be if list empty.

  在此方法中，它在兩種情況下返回-1 ，首先是元素在列表中不存在，然后返回-1 ，第二種情況是如果列表為空。

Syntax:

句法：

public int indexOf(Object o){}

Parameter(s):

參數：

We can pass only one object as a parameter in the method of the linked list.

在鏈表的方法中，我們只能傳遞一個對象作為參數。

Return value:

返回值：

The return type of this method is int type (i.e. number type ) that means this method returns the index of the first occurrence of the element after execution else returns -1.

此方法的返回類型為int類型(即數字類型)，這意味著此方法在執行后返回第一次出現的元素的索引，否則返回-1 。

Java程序演示LinkedList indexOf(Object o)方法的示例 (Java program to demonstrate example of LinkedList indexOf(Object o) method)

Case 1: Linked List with unique elements

情況1：具有唯一元素的鏈接列表

import java.util.LinkedList;public class LinkList {public static void main(String[] args) {LinkedList list = new LinkedList();// use add() method to add elements in the list list.add(10);list.add(20);list.add(30);list.add(40);list.add(50);// Current list OutputSystem.out.println("The Current list is:" + list);// We will find the position of element 30 in the linked listSystem.out.println("The position of element 30 in the list is:" + list.indexOf(30));} }

Output

輸出量

D:\Programs>javac LinkList.javaD:\Programs>java LinkList The Current list is:[10, 20, 30, 40, 50] The position of element 30 in the list is:2

Case 2: Linked List with duplicate elements

情況2：具有重復元素的鏈表

import java.util.LinkedList;public class LinkList {public static void main(String[] args) {LinkedList list = new LinkedList();// use add() method to add elements in the list list.add(10);list.add(20);list.add(30);list.add(20);list.add(40);list.add(20);list.add(50);// Current list OutputSystem.out.println("The Current list is:" + list);// We will find the position of element 20 in the linked list //and here 20 comes thrice in a list so it will return // index of first occurrence System.out.println("The position of element 20 in the list is:" + list.indexOf(20));} }

Output

輸出量

D:\Programs>javac LinkList.javaD:\Programs>java LinkList The Current list is:[10, 20, 30, 20, 40, 20, 50] The position of element 30 in the list is:1

翻譯自: https://www.includehelp.com/java/linkedlist-public-int-indexof-object-o-method-with-example.aspx

總結

以上是生活随笔為你收集整理的Java LinkedList公共int indexOf（Object o）方法（带示例）的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。