Electrification Plan
生活随笔
收集整理的這篇文章主要介紹了
Electrification Plan
小編覺得挺不錯的,現(xiàn)在分享給大家,幫大家做個參考.
http://acm.timus.ru/problem.aspx?space=1&num=1982
題解:最小生成樹
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int ans,cnt,flag,temp,sum; int pre[N],a[N]; char str; struct node{int u,v,w;bool operator<(const node&S)const{return w<S.w;} }e[N]; int find(int x){return pre[x]==x?x:pre[x]=find(pre[x]);} bool marge(int u,int v){int tu=find(u);int tv=find(v);if(tu!=tv){pre[tu]=tv;return 1;}return 0; } int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){scanf("%d%d",&n,&k);for(int i=1;i<=n;i++){pre[i]=i;}for(int i=1;i<=k;i++){scanf("%d",&a[i]);if(i!=1)marge(a[i-1],a[i]);}for(int i=1;i<=n;i++){for(int j=1;j<=n;j++){scanf("%d",&m);if(i<=j)continue;e[++cnt].u=i;e[cnt].v=j;e[cnt].w=m;}}sort(e+1,e+cnt+1);for(int i=1;i<=cnt;i++){if(marge(e[i].u,e[i].v)){ans+=e[i].w;}}cout<<ans<<endl;//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
總結
以上是生活随笔為你收集整理的Electrification Plan的全部內(nèi)容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: Ant Trip
- 下一篇: Road Construction