像這樣的東西.

Select people.id, people.name, count(interest.id)

from people

left join people_interests on people.id = people_interests.peopleid

left join interests on people_interests.interestid = interests.interest.id

where interests.id in (select id from interests where interests.peopleid = @inputuserid)

group by people.id, people.name

order by count(interest.id)

英語(可能會或可能不會更清楚.)

>選擇人員姓名和他們共享的興趣數量

>從人員表

>加入那個表的興趣表

>只是我們想要匹配的人的利益.

>(按人群分組

>并按匹配的興趣數量排序.)

更新沒有子查詢但不太清楚

Select people.id, people.name, count(interest.id)

from people

left join people_interests on people.id = people_interests.peopleid

left join interests on people_interests.interestid = interests.interest.id

inner join interest i2 on (interests.id = i2.id and i2.people_id = @inputuserid)

group by people.id, people.name

order by count(interest.id)

總結

以上是生活随笔為你收集整理的mysql复杂查询sql_mysql – 复杂的SQL查询,很多很多的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。