javascript
4种方法让SpringMVC接收多个对象（转：http://blog.csdn.net/lutinghuan/article/details/46820023）
問題背景：
我要在一個表單里同時一次性提交多名乘客的個人信息到SpringMVC，前端HTML和SpringMVC Controller里該如何處理？
第1種方法：表單提交，以字段數組接收；
第2種方法：表單提交，以BeanListModel接收；
第3種方法：將Json對象序列化成Json字符串提交，以List接收；
第4種方法：將表單對象序列化成Json字符串提交，以List接收；
第4種方法其實是第3種方法的升級，就是將表單轉成Json對象，再轉成Json字符串提交；
然而，第4種方法還不支持含有多選控件表單的提交，故應該還有第5種加強版的方法。
以上4種方法都共用同一個User實體類，代碼如下：
public class User {
?
??? privateInteger id;
??? privateString name;
??? privateString pwd;
?
???@Override
??? publicString toString() {
???????return "User{" +
??????????????? "id=" + id +
??????????????? ", name='" + name + '\''+
???????????????", pwd='" + pwd+ '\'' +
??????????????? '}';
??? }
??? //.......后面還有getter、setter方法，省略了
?}
第1種方法：表單提交，以字段數組接收
HTML代碼如下：
??? <formaction="/user/submitUserList_1" method="post">
???????ID:<input type="text" name="id"><br/>
???????Username:<input type="text" name="name"><br/>
???????Password:<input type="text" name="pwd"><br/><br/>
?
???????ID:<input type="text" name="id"><br/>
???????Username:<input type="text" name="name"><br/>
???????Password:<input type="text" name="pwd"><br/><br/>
???????<input type="submit" value="submit">
??? </form>
Java代碼如下：
???@RequestMapping(value = "/submitUserList_1", method={RequestMethod.POST})
???@ResponseBody
???public String submitUserList_1(HttpServletResponse response,Integer[] id,String[] name, String[] pwd)
??????????????????????????? throws Exception{
???????String result = "";
???????if(id == null || id.length <= 0){ return "No any ID.中文"; }
???????List<User> userList = new ArrayList<User>();
???????for (int i = 0; i < id.length; i++ ) {
???????????User user = new User();
???????????user.setId(id[i]);
???????????user.setName(name[i]);
???????????user.setPwd(pwd[i]);
???????????userList.add(user);
???????}
???????result = this.showUserList(userList);
???????return result;
??? }
第2種方法：表單提交，以BeanListModel接收
HTML代碼如下：
??? <formaction="/user/submitUserList_2" method="post">
???????ID:<input type="text" name="users[0].id"><br/>
???????Username:<input type="text" name="users[0].name"><br/>
???????Password:<input type="text"name="users[0].pwd"><br/><br/>
?
???????ID:<input type="text" name="users[2].id"><br/>
???????Username:<input type="text" name="users[2].name"><br/>
???????Password:<input type="text" name="users[2].pwd"><br/><br/>
???????<input type="submit" value="Submit">
??? </form>
Java代碼：
除了剛才公用的User類，還要封裝一個User的容器類UserModel：
public class UserModel {
??? privateList<User> users;
?
??? publicList<User> getUsers() {
???????return users;
??? }
?
??? publicvoid setUsers(List<User> users) {
???????this.users = users;
??? }
?
??? publicUserModel(List<User> users) {
???????super();
???????this.users = users;
??? }
?
??? publicUserModel() {
???????super();
??? }
?
}
SpringMVC Controller方法：
??? @RequestMapping(value= "/submitUserList_2", method ={RequestMethod.POST})
??? @ResponseBody
??? publicString submitUserList_2(UserModel users)
???????????throws Exception{
???????String result = "";
???????List<User> userList = users.getUsers();
???????if(userList == null || userList.size() <= 0){ return "No any ID.中文"; }
???????result = this.showUserList(userList);
???????return result;
??? }
第3種方法：將Json對象序列化成Json字符串提交，以List接收
HTML代碼：
<head>
??? <title>submitUserList_3</title>
??? <metahttp-equiv="content-type" content="text/html;charset=utf-8">
??? <scriptlanguage="JavaScript" src="/js/jquery.min.js" ></script>
??? <scriptlanguage="JavaScript" src="/js/jquery.json.min.js"></script>
??? <scripttype="text/javascript" language="JavaScript">
???????function submitUserList_3() {alert("ok");
???????????var customerArray = new Array();
???????????customerArray.push({id: "1", name: "李四",pwd: "123"});
???????????customerArray.push({id: "2", name: "張三",pwd: "332"});
???????????$.ajax({
??????????????? url: "/user/submitUserList_3",
??????????????? type: "POST",
??????????????? contentType : 'application/json;charset=utf-8',//設置請求頭信息
??????????????? dataType:"json",
??????????????? //data:JSON.stringify(customerArray),??? //將Json對象序列化成Json字符串，JSON.stringify()原生態方法
??????????????? data:$.toJSON(customerArray),??????????? //將Json對象序列化成Json字符串，toJSON()需要引用jquery.json.min.js
??????????????? success: function(data){
??????????????????? alert(data);
??????????????? },
??????????????? error: function(res){
??????????????????? alert(res.responseText);
??????????????? }
???????????});
???????}
??? </script>
</head>
?
<body>
??? <h1>submitUserList_3</h1>
??? <inputid="submit" type="button" value="Submit" οnclick="submitUserList_3();">
</body>
Java代碼：
??? @RequestMapping(value= "/submitUserList_3", method ={RequestMethod.POST})
??? @ResponseBody
??? publicString submitUserList_3(@RequestBody List<User> users)
???????????throws Exception{
???????String result = "";
???????if(users == null || users.size() <= 0){ return "No any ID.中文"; }
???????result = this.showUserList(users);
???????return result;
??? }
第4種方法：將表單對象序列化成Json字符串提交，以List接收
HTML代碼：
<!DOCTYPE HTML PUBLIC "-//W3C//DTDHTML 4.01 Transitional//EN"
???????"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
??? <title>submitUserList_4</title>
??? <metahttp-equiv="content-type" content="text/html;charset=utf-8">
??? <scriptlanguage="JavaScript" src="/js/jquery.min.js" ></script>
??? <scripttype="text/javascript" language="JavaScript">
???????//將表單序列化成json格式的數據(但不適用于含有控件的表單，例如復選框、多選的select)
???????(function($){
???????????$.fn.serializeJson = function(){
??????????????? var jsonData1 = {};
??????????????? var serializeArray = this.serializeArray();
??????????????? // 先轉換成{"id":["12","14"], "name":["aaa","bbb"],"pwd":["pwd1","pwd2"]}這種形式
??????????????? $(serializeArray).each(function() {
??????????????????? if (jsonData1[this.name]) {
??????????????????????? if($.isArray(jsonData1[this.name])) {
??????????????????????????? jsonData1[this.name].push(this.value);
??????????????????????? } else {
??????????????????????????? jsonData1[this.name]= [jsonData1[this.name], this.value];
??????????????????????? }
??????????????????? } else {
??????????????????????? jsonData1[this.name] = this.value;
??????????????????? }
??????????????? });
??????????????? // 再轉成[{"id":"12", "name": "aaa","pwd":"pwd1"},{"id": "14","name": "bb", "pwd":"pwd2"}]的形式
??????????????? var vCount = 0;
??????????????? // 計算json內部的數組最大長度
??????????????? for(var item in jsonData1){
??????????????????? var tmp =$.isArray(jsonData1[item]) ? jsonData1[item].length : 1;
??????????????????? vCount = (tmp > vCount)? tmp : vCount;
??????????????? }
?
??????????????? if(vCount > 1) {
??????????????????? var jsonData2 = new Array();
??????????????????? for(var i = 0; i <vCount; i++){
??????????????????????? var jsonObj = {};
??????????????????????? for(var item in jsonData1){
??????????????????????????? jsonObj[item] =jsonData1[item][i];
??????????????????????? }
???????????????????????jsonData2.push(jsonObj);
??????????????????? }
??????????????????? return JSON.stringify(jsonData2);
??????????????? }else{
???? ???????????????return "[" + JSON.stringify(jsonData1)+ "]";
??????????????? }
???????????};
???????})(jQuery);
?
???????function submitUserList_4() {alert("ok");
???????????var jsonStr = $("#form1").serializeJson();
???????????//console.log("jsonStr:\r\n" + jsonStr);
???????????//alert(jsonStr);
???????????$.ajax({
??????????????? url: "/user/submitUserList_4",
??????????????? type: "POST",
??????????????? contentType : 'application/json;charset=utf-8',//設置請求頭信息
??????????????? dataType:"json",
??? ????????????data: jsonStr,
??????????????? success: function(data){
??????????????????? alert(data);
??????????????? },
??????????????? error: function(res){
??????????????????? alert(res.responseText);
??????????????? }
???????????});
???????}
??? </script>
</head>
?
<body>
??? <h1>submitUserList_4</h1>
??? <formid="form1">
???????ID:<input type="text" name="id"><br/>
???????Username:<input type="text" name="name"><br/>
???????Password:<input type="text" name="pwd"><br/><br/>
?
???????ID:<input type="text" name="id"><br/>
???????Username:<input type="text" name="name"><br/>
???????Password:<input type="text" name="pwd"><br/><br/>
???????<input type="button" value="submit" οnclick="submitUserList_4();">
??? </form>
</body>
</html>
Java代碼：
??? @RequestMapping(value= "/submitUserList_4", method ={RequestMethod.POST})
??? @ResponseBody
??? publicString submitUserList_4(@RequestBody List<User> users)
???????????throws Exception{
???????String result = "";
???????if(users == null || users.size() <= 0){ return "No any ID.中文"; }
???????result = this.showUserList(users);
???????return result;
??? }
總結：
第1、2種方法其實都有一個共同的BUG：假如提交三條記錄時，前面兩條記錄的某些字段不填值的話，在SpringMVC里接收不準確了。而且，每2種方法在HMTL中需要給name屬性添加[下標]，如果下標有跨度的話（比如第一組控件下標是0,第二組下標是2），那么SpringMVC里其實的是0到2三個對象的，默認下標是1的那個對象全為null值。
第3、4種方法最實用。
以上方法參考自以下URL：
http://www.cnblogs.com/wsw0515/p/3582627.html
http://www.oschina.net/question/917732_106601
http://jxd-zxf.iteye.com/blog/2072300
http://www.tashan10.com/jquery-jiang-biao-dan-xu-lie-hua-wei-jsondui-xiang/
?
總結
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