? ? ? ? ? ? ? ? ? ? ? ? ? ?判斷字符串含有漢字

需求描述

需求：檢索含有漢字的字符串.

解決方法:這里通過函數CHAR_LENGTH對比LENGTH進行對比來判斷.

注: 數據庫數據集SQL腳本詳見如下鏈接地址

員工表結構和數據初始化SQL腳本

SQL代碼

--Mysql: SELECT data,LENGTH(data) AS Len_data,CHAR_LENGTH(data) AS CharLen_Data,HEX(data) AS HexData FROM ( SELECT 'Hello,World,SQL' AS dataUNION ALL SELECT 'Data,Arithmetic' AS dataUNION ALL SELECT 'Science中國' AS dataUNION ALL SELECT '上S海H' AS data??? )A WHERE LENGTH(data)<> CHAR_LENGTH(data)

執行結果

/* 注: LENGTH() returns the length of the string measured in bytes. CHAR_LENGTH() returns the length of the string measured in characters. LENGTH:是計算字節的長度.一個漢字是算三個字符,一個數字或字母算一個字符 CHAR_LENGTH:漢字、數字、字母都算是一個字符*/-- 或者通過字符串的十六進制并結合REGEXP來判斷. SELECT data,HEX(data) AS HexData FROM ( SELECT 'Hello,World,SQL' AS dataUNION ALL SELECT 'Data,Arithmetic' AS dataUNION ALL SELECT 'Science中國' AS dataUNION ALL SELECT '上S海H' AS data )A WHERE HEX(data) REGEXP '^(..)*(E[4-9])'

--SQL Server: SELECT data FROM ( SELECT 'Hello,World,SQL' AS dataUNION ALL SELECT 'Data,Arithmetic' AS dataUNION ALL SELECT 'Science中國' AS dataUNION ALL SELECT '上S海H' AS data )A WHERE data LIKE '%[吖-座]%' --或者利用PATINDEX函數進行判斷SELECT data FROM ( SELECT 'Hello,World,SQL' AS dataUNION ALL SELECT 'Data,Arithmetic' AS dataUNION ALL SELECT 'Science中國' AS dataUNION ALL SELECT '上S海H' AS data )A WHERE PATINDEX('%[吖-座]%',data) > 0

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