選項1：您可以使用下面這樣的else條件。在def Input_Q_bounds(lower, upper):

delta_x = .1

# since there are 100 iterations

J = np.zeros(101)

for i in range(101):

Q_i = (i * delta_x) + (delta_x / 2)

if lower <= Q_i <= upper:

Q = 1

else:

Q = 0

# now fill the matrix

J[i] = (Q + (9.5 * (J[i - 1]))) / 10.5

J_analytical = Q * (np.exp(upper - 10) + (np.exp(lower - 10))

else:

print(J_analytical)

print(J[100])

if __name__ == "__main__":

Input_Q_bounds(lower, upper)

選項2：下面的解決方案是使用全局變量

^{pr2}$

選項3：從函數返回值。在def Input_Q_bounds(lower, upper):

delta_x = .1

# since there are 100 iterations

J = np.zeros(101)

for i in range(101):

Q_i = (i * delta_x) + (delta_x / 2)

if lower <= Q_i <= upper:

Q = 1

else:

Q = 0

# now fill the matrix

J[i] = (Q + (9.5 * (J[i - 1]))) / 10.5

J_analytical = Q * (np.exp(upper - 10) + (np.exp(lower - 10))

return J[100], J_analytical

if __name__ == "__main__":

Input_Q_bounds(lower, upper)

總結

以上是生活随笔為你收集整理的pythonfor循环100次_在for循环中只打印一次的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。