用基于密度的聚類算法，計算坐標點聚集地，很好用。

import pandas as pd

import numpy as np

from sklearn.cluster import DBSCAN

from sklearn import metrics

from sklearn.cluster import KMeans

import os

def dbscan(input_file):

columns=['lon','lat']

in_df = pd.read_csv(input_file, sep=',', header=None, names=columns)

#print(in_df.head(10))

#represent GPS points as (lon, lat)

coords = in_df.as_matrix(columns=['lon','lat'])

#earth's radius in km

kms_per_radian = 6371.0086

#define epsilon as 0.5 kilometers, converted to radians for use by haversine

#This uses the 'haversine' formula to calculate the great-circle distance between two points

# that is, the shortest distance over the earth's surface

# http://www.movable-type.co.uk/scripts/latlong.html

epsilon = 0.5 / kms_per_radian

# radians() Convert angles from degrees to radians

db = DBSCAN(eps=epsilon, min_samples=15, algorithm='ball_tree', metric='haversine').fit(np.radians(coords))

cluster_labels = db.labels_

# get the number of clusters (ignore noisy samples which are given the label -1)

num_clusters = len(set(cluster_labels) - set([-1]))

print( 'Clustered ' + str(len(in_df)) + ' points to ' + str(num_clusters) + ' clusters')

# turn the clusters in to a pandas series

#clusters = pd.Series([coords[cluster_labels == n] for n in range(num_clusters)])

#print(clusters)

kmeans = KMeans(n_clusters=1, n_init=1, max_iter=20, random_state=20)

for n in range(num_clusters):

# print('Cluster ', n, ' all samples:')

one_cluster = coords[cluster_labels == n]

#print(one_cluster[:1])

#clist = one_cluster.tolist()

#print(clist[0])

kk = kmeans.fit(one_cluster)

print(kk.cluster_centers_)

def main():

path = './datas'

filelist = os.listdir(path)

for f in filelist:

datafile = os.path.join(path,f)

print(datafile)

dbscan(datafile)

if __name__ == '__main__':

main()

下面幾個博客，寫的很好：

https://www.cnblogs.com/pinard/p/6208966.html

http://shiyanjun.cn/archives/1288.html

https://www.biaodianfu.com/dbscan.html

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