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【转】函数调用时堆栈变化

發布時間:2024/9/5 编程问答 29 豆豆
生活随笔 收集整理的這篇文章主要介紹了 【转】函数调用时堆栈变化 小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
【原文】http://blog.csdn.net/xupan_jsj/article/details/7459630
  • int?goo(int?a,?int?b)??
  • {??
  • ????return?a?+?b;??
  • }??
  • ??
  • void?foo()??
  • {??
  • ????int?a[]?=?{1,?2,?3};??
  • ????int?result?=?goo(a[1],?a[2]);??
  • ????printf("result:?%d",?result);??
  • }??

  • VS2010下編譯

    ?

    ?

    foo函數部分匯編:

    ?

    [cpp]?view plaincopyprint?
  • 00EB3890??push????????ebp????
  • 00EB3891??mov?????????ebp,esp????
  • 00EB3893??sub?????????esp,0E4h????
  • 00EB3899??push????????ebx????
  • 00EB389A??push????????esi????
  • 00EB389B??push????????edi????
  • 00EB389C??lea?????????edi,[ebp-0E4h]????
  • 00EB38A2??mov?????????ecx,39h????
  • 00EB38A7??mov?????????eax,0CCCCCCCCh????
  • 00EB38AC??rep?stos????dword?ptr?es:[edi]????
  • 00EB38AE??mov?????????eax,dword?ptr?[___security_cookie?(0EB7000h)]????
  • 00EB38B3??xor?????????eax,ebp????
  • 00EB38B5??mov?????????dword?ptr?[ebp-4],eax????
  • ????int?a[]?=?{1,?2,?3};??
  • 00EB38B8??mov?????????dword?ptr?[ebp-14h],1????
  • 00EB38BF??mov?????????dword?ptr?[ebp-10h],2????
  • 00EB38C6??mov?????????dword?ptr?[ebp-0Ch],3????
  • ????int?result?=?goo(a[1],?a[2]);??
  • 00EB38CD??mov?????????eax,dword?ptr?[ebp-0Ch]????
  • 00EB38D0??push????????eax????
  • 00EB38D1??mov?????????ecx,dword?ptr?[ebp-10h]????
  • 00EB38D4??push????????ecx????
  • 00EB38D5??call????????goo?(0EB11E5h)????
  • 00EB38DA??add?????????esp,8????
  • [cpp]?view plaincopyprint?
  • 00EB3890??push????????ebp????
  • 00EB3891??mov?????????ebp,esp????
  • 00EB3893??sub?????????esp,0E4h????
  • 00EB3899??push????????ebx????
  • 00EB389A??push????????esi????
  • 00EB389B??push????????edi????
  • 00EB389C??lea?????????edi,[ebp-0E4h]????
  • 00EB38A2??mov?????????ecx,39h????
  • 00EB38A7??mov?????????eax,0CCCCCCCCh????
  • 00EB38AC??rep?stos????dword?ptr?es:[edi]????
  • 00EB38AE??mov?????????eax,dword?ptr?[___security_cookie?(0EB7000h)]????
  • 00EB38B3??xor?????????eax,ebp????
  • 00EB38B5??mov?????????dword?ptr?[ebp-4],eax????
  • ????int?a[]?=?{1,?2,?3};??
  • 00EB38B8??mov?????????dword?ptr?[ebp-14h],1????
  • 00EB38BF??mov?????????dword?ptr?[ebp-10h],2????
  • 00EB38C6??mov?????????dword?ptr?[ebp-0Ch],3????
  • ????int?result?=?goo(a[1],?a[2]);??
  • 00EB38CD??mov?????????eax,dword?ptr?[ebp-0Ch]????
  • 00EB38D0??push????????eax????
  • 00EB38D1??mov?????????ecx,dword?ptr?[ebp-10h]????
  • 00EB38D4??push????????ecx????
  • 00EB38D5??call????????goo?(0EB11E5h)????
  • 00EB38DA??add?????????esp,8????

  • goo函數完整匯編:

    ?

    ?

    ?

    [cpp]?view plaincopyprint?
  • 00EB1580??push????????ebp????
  • 00EB1581??mov?????????ebp,esp????
  • 00EB1583??sub?????????esp,0C0h????
  • 00EB1589??push????????ebx????
  • 00EB158A??push????????esi????
  • 00EB158B??push????????edi????
  • 00EB158C??lea?????????edi,[ebp-0C0h]????
  • 00EB1592??mov?????????ecx,30h????
  • 00EB1597??mov?????????eax,0CCCCCCCCh????
  • 00EB159C??rep?stos????dword?ptr?es:[edi]????
  • ????return?a?+?b;??
  • 00EB159E??mov?????????eax,dword?ptr?[a]????
  • 00EB15A1??add?????????eax,dword?ptr?[b]????
  • }??
  • 00EB15A4??pop?????????edi????
  • 00EB15A5??pop?????????esi????
  • 00EB15A6??pop?????????ebx????
  • 00EB15A7??mov?????????esp,ebp????
  • 00EB15A9??pop?????????ebp????
  • 00EB15AA??ret????
  • [cpp]?view plaincopyprint?
  • 00EB1580??push????????ebp????
  • 00EB1581??mov?????????ebp,esp????
  • 00EB1583??sub?????????esp,0C0h????
  • 00EB1589??push????????ebx????
  • 00EB158A??push????????esi????
  • 00EB158B??push????????edi????
  • 00EB158C??lea?????????edi,[ebp-0C0h]????
  • 00EB1592??mov?????????ecx,30h????
  • 00EB1597??mov?????????eax,0CCCCCCCCh????
  • 00EB159C??rep?stos????dword?ptr?es:[edi]????
  • ????return?a?+?b;??
  • 00EB159E??mov?????????eax,dword?ptr?[a]????
  • 00EB15A1??add?????????eax,dword?ptr?[b]????
  • }??
  • 00EB15A4??pop?????????edi????
  • 00EB15A5??pop?????????esi????
  • 00EB15A6??pop?????????ebx????
  • 00EB15A7??mov?????????esp,ebp????
  • 00EB15A9??pop?????????ebp????
  • 00EB15AA??ret????

  • ?

    ?

    foo函數push ebp, mov ebp, esp后

    保存原ebp,設定新的ebp為當前esp位置

    ?

    ?

    sub esp, 0E4h

    給局部變量分配足夠大的棧空間

    ?

    保存原先的一些寄存器值,每次push,esp繼續向下移

    ?

    ?

    為局部變量a數組賦值

    ?

    調用goo前Push兩個參數,esp繼續下移

    ?

    call goo函數時,cpu自動push下一條指令地址,esp繼續下移

    在goo函數中,同樣保存foo函數中的ebp值,設定新的ebp,esp等

    ?

    在執行玩goo函數最后幾句指令時,edi, esi, ebx恢復,esp同時也編程goo中ebp的位置,ebp恢復至foo函數原來的位置(pop ebp)

    下一條指令也裝入IP(ret指令),esp繼續向上一步

    ?

    foo函數中的add esp, 8將esp值繼續往上(清除函數參數)

    清除函數參數的工作也可通過ret X在goo函數返回時設定(這樣的話不必在每次調用點上加上add esp, X指令縮短了編譯出來的文件大小,但在子函數中清除將不能做到printf等的可變參數個數功能,因為子函數不知道具體有多少要參數進入了,只有調用處才知道)

    轉載于:https://www.cnblogs.com/zzmx/p/4166443.html

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