有一個復雜的 if-else 語句

if (date.before(SUMMER_START) || date.after(SUMMER_END)) {charge = quantity * winterRate + winterServiceCharge; } else {charge = quantity * summerRate; }

重構：?從if-else 中分別提煉出獨立函數

if (notSummer(date)) {charge = winterCharge(quantity); } else {charge = summerCharge(quantity); }private boolean notSummer(Date date) {return date.before(SUMMER_START) || date.after(SUMMER_END); }private double summerCharge(int quantity) {return quantity * summerRate; }private double winterCharge(int quantity) {return quantity * winterRate + winterServiceCharge; }

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