Java黑皮書課后題第9章：*9.11（代數：2*2的線性方程）為一個2*2的線性方程設計一個名為LinearEquation的類

• 題目
• • 破題
• 代碼
• • Test10
  • Test11_LinearEquation
  • 運行結果
• UML圖

題目

破題

Test11：測試程序
Test11_LinearEquation：實現題目要求

點擊跳轉練習題3.3

代碼

Test10

import java.util.Scanner;public class Test11 {public static void main(String[] args) {// 獲取用戶輸入Scanner input = new Scanner(System.in);System.out.println("Enter a, b, c, d, e, f: ");double a = input.nextInt(), b = input.nextInt(), c = input.nextInt();double d = input.nextInt(), e = input.nextInt(), f = input.nextInt();// 傳入構造方法Test11_LinearEquation le = new Test11_LinearEquation(a, b, c, d, e, f);// 判斷是否有結果boolean bool = le.isSolvable();if (bool){System.out.println("x is " + le.getX() + " and y is " + le.getY());} elseSystem.out.println("The equation has no solution");} }

Test11_LinearEquation

public class Test11_LinearEquation {private double a, b, c, d, e, f;// 構造方法public Test11_LinearEquation (double a, double b, double c, double d, double e, double f){this.a = a;this.b = b;this.c = c;this.d = d;this.e = e;this.f = f;}// getterpublic double getA() {return a;}public double getB() {return b;}public double getC() {return c;}public double getD() {return d;}public double getE() {return e;}public double getF() {return f;}// isSolvable方法public boolean isSolvable(){boolean bool = false;if (a * d - b * c != 0){bool = true;}return bool;}// getX和getYpublic double getX(){return (e * d - b * f) / (a * d - b * c);}public double getY(){return (a * f - e * c) / (a * d - b * c);} }

運行結果

Enter a, b, c, d, e, f: 1 2 3 4 5 6 x is -4.0 and y is 4.5

UML圖

總結

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