刷題繼續

上一期和大家分享了前10道題，今天繼續來刷11~20

Question 11:

Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a comma separated sequence.

Example:

0100,0011,1010,1001

Then the output should be:

1010

Notes: Assume the data is input by console.

解法一

def check(x): # check function returns true if divisible by 5

return int(x,2)%5 == 0 # int(x,b) takes x as string and b as base from which

# it will be converted to decimal

data = input().split(',')

data = list(filter(check,data)) # in filter(func,object) function, elements are picked from 'data' if found True by 'check' function

print(",".join(data))

解法二

value = []

items=[int(x) for x in input().split(',')]

result = " ".join(str(x) for x in items if x %5==0 )

print(",".join(result))

解法三

data = input().split(',')

data = list(filter(lambda i:int(i,2)%5==0,data))

print(",".join(data))

Question 12:

Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each digit of the number is an even number.The numbers obtained should be printed in a comma-separated sequence on a single line.

解法一

values = []

for i in range(1000, 3001):

s = str(i)

if (int(s[0])%2==0) and (int(s[1])%2==0) and (int(s[2])%2==0) and (int(s[3])%2==0):

values.append(s)

print (",".join(values))

解法二

lst = []

for i in range(1000,3001):

flag = 1

for j in str(i): # every integer number i is converted into string

if ord(j)%2 != 0: # ord returns ASCII value and j is every digit of i

flag = 0 # flag becomes zero if any odd digit found

if flag == 1:

lst.append(str(i)) # i is stored in list as string

print(",".join(lst))

解法三

def check(element):

return all(ord(i)%2 == 0 for i in element) # all returns True if all digits i is even in element

lst = [str(i) for i in range(1000,3001)] # creates list of all given numbers with string data type

lst = list(filter(check,lst)) # filter removes element from list if check condition fails

print(",".join(lst))

解法四

lst = [str(i) for i in range(1000,3001)]

lst = list(filter(lambda i:all(ord(j)%2 == 0 for j in i),lst )) # using lambda to define function inside filter function

print(",".join(lst))

Question 13:

Write a program that accepts a sentence and calculate the number of letters and digits.

Suppose the following input is supplied to the program:

hello world! 123

Then, the output should be:

LETTERS 10

DIGITS 3

解法一

text_input = input()

d={"DIGITS":0, "LETTERS":0,'SPACE':0}

d['DIGITS']= sum(c.isdigit() for c in text_input)

d['LETTERS']= sum(c.isalpha() for c in text_input)

d['SPACE'] = sum(c.isspace() for c in text_input)

for k,v in d.items():

print(k,v)

解法二

word = input()

letter,digit = 0,0

for i in word:

if ('a'<=i and i<='z') or ('A'<=i and i<='Z'):

letter+=1

if '0'<=i and i<='9':

digit+=1

print("LETTERS {0}\nDIGITS {1}".format(letter,digit))

解法三

word = input()

letter,digit = 0,0

for i in word:

letter+=i.isalpha() # returns True if alphabet

digit+=i.isnumeric() # returns True if numeric

print("LETTERS %d\nDIGITS %d"%(letter,digit)) # two different types of formating method is shown in both solution

Question 14:

Write a program that accepts a sentence and calculate the number of upper case letters and lower case letters.

Suppose the following input is supplied to the program:

Hello world!

Then, the output should be:

UPPER CASE 1

LOWER CASE 9

解法一

word = input()

upper,lower = 0,0

for i in word:

if 'a'<=i and i<='z' :

lower+=1

if 'A'<=i and i<='Z':

upper+=1

print("UPPER CASE {0}\nLOWER CASE {1}".format(upper,lower))

解法二

text_input = input()

d={"UPPER CASE":0, "LOWER CASE":0}

for c in text_input:

if c.isupper():

d["UPPER CASE"]+=1

elif c.islower():

d["LOWER CASE"]+=1

else:

pass

print ("UPPER CASE", d["UPPER CASE"])

print ("LOWER CASE", d["LOWER CASE"])

解法三

word = input()

upper = sum(1 for i in word if i.isupper())

lower = sum(1 for i in word if i.islower())

print("UPPER CASE {0}\nLOWER CASE {1}".format(upper,lower))

Question 15:

Write a program that computes the value of a+aa+aaa+aaaa with a given digit as the value of a.

Suppose the following input is supplied to the program:

9

Then, the output should be:

11106

解法一

a = input()

total,tmp = 0,str() # initialing an integer and empty string

for i in range(4):

tmp+=a # concatenating 'a' to 'tmp'

total+=int(tmp) # converting string type to integer type

print(total)

解法二

a = input()

total = int(a) + int(2*a) + int(3*a) + int(4*a) # N*a=Na, for example a="23", 2*a="2323",3*a="232323"

print(total)

Question 16:

Use a list comprehension to square each odd number in a list. The list is input by a sequence of comma-separated numbers.

Suppose the following input is supplied to the program:

1,2,3,4,5,6,7,8,9

Then, the output should be:

1,3,5,7,9

解法一

values = input()

numbers = [x for x in values.split(",") if int(x)%2!=0]

print (",".join(numbers))

Question 17:

Write a program that computes the net amount of a bank account based a transaction log from console input. The transaction log format is shown as following:

D 100

W 200

D means deposit while W means withdrawal.

Suppose the following input is supplied to the program:

D 300

D 300

W 200

D 100

Then, the output should be:

500

解法一

netAmount = 0

while True:

s = input()

if not s:

break

values = s.split(" ")

operation = values[0]

amount = int(values[1])

if operation=="D":

netAmount+=amount

elif operation=="W":

netAmount-=amount

else:

pass

print(netAmount)

解法二

total = 0

while True:

s = input().split()

if not s: # break if the string is empty

break

cm,num = map(str,s)

if cm=='D':

total+=int(num)

if cm=='W':

total-=int(num)

print(total)

Question 18:

A website requires the users to input username and password to register. Write a program to check the validity of password input by users.

Following are the criteria for checking the password:

At least 1 letter between [a-z]

At least 1 number between [0-9]

At least 1 letter between [A-Z]

At least 1 character from [$#@]

Minimum length of transaction password: 6

Maximum length of transaction password: 12

Your program should accept a sequence of comma separated passwords and will check them according to the above criteria. Passwords that match the criteria are to be printed, each separated by a comma.

Example

If the following passwords are given as input to the program:

ABd1234@1,a F1#,2w3E*,2We3345

Then, the output of the program should be:

ABd1234@1

解法一

import re

value = []

items=[x for x in input().split(',')]

for p in items:

if (len(p)<6 or len(p)>12):

break

elif not re.search("[a-z]",p):

break

elif not re.search("[0-9]",p):

break

elif not re.search("[A-Z]",p):

break

elif not re.search("[$#@]",p):

break

elif re.search("\s",p):

break

else:

value.append(p)

break

print (",".join(value))

解法二

def is_low(x): # Returns True if the string has a lowercase

for i in x:

if 'a'<=i and i<='z':

return True

return False

def is_up(x): # Returns True if the string has a uppercase

for i in x:

if 'A'<= i and i<='Z':

return True

return False

def is_num(x): # Returns True if the string has a numeric digit

for i in x:

if '0'<=i and i<='9':

return True

return False

def is_other(x): # Returns True if the string has any "$#@"

for i in x:

if i=='$' or i=='#' or i=='@':

return True

return False

s = input().split(',')

lst = []

for i in s:

length = len(i)

if 6 <= length and length <= 12 and is_low(i) and is_up(i) and is_num(i) and is_other(i): #Checks if all the requirments are fulfilled

lst.append(i)

print(",".join(lst))

解法三

def check(x):

cnt = (6<=len(x) and len(x)<=12)

for i in x:

if i.isupper():

cnt+=1

break

for i in x:

if i.islower():

cnt+=1

break

for i in x:

if i.isnumeric():

cnt+=1

break

for i in x:

if i=='@' or i=='#'or i=='$':

cnt+=1

break

return cnt == 5 # counting if total 5 all conditions are fulfilled then returns True

s = input().split(',')

lst = filter(check,s) # Filter function pick the words from s, those returns True by check() function

print(",".join(lst))

解法四

import re

s = input().split(',')

lst = []

for i in s:

cnt = 0

cnt+=(6<=len(i) and len(i)<=12)

cnt+=bool(re.search("[a-z]",i)) # here re module includes a function re.search() which returns the object information

cnt+=bool(re.search("[A-Z]",i)) # of where the pattern string i is matched with any of the [a-z]/[A-z]/[0=9]/[@#$] characters

cnt+=bool(re.search("[0-9]",i)) # if not a single match found then returns NONE which converts to False in boolean

cnt+=bool(re.search("[@#$]",i)) # expression otherwise True if found any.

if cnt == 5:

lst.append(i)

print(",".join(lst))

Question 19:

You are required to write a program to sort the (name, age, score) tuples by ascending order where name is string, age and score are numbers. The tuples are input by console. The sort criteria is:

1: Sort based on name

2: Then sort based on age

3: Then sort by score

The priority is that name > age > score.

If the following tuples are given as input to the program:

Tom,19,80

John,20,90

Jony,17,91

Jony,17,93

Json,21,85

Then, the output of the program should be:

[('John', '20', '90'), ('Jony', '17', '91'), ('Jony', '17', '93'), ('Json', '21', '85'), ('Tom', '19', '80')]

解法一

lst = []

while True:

s = input().split(',')

if not s[0]: # breaks for blank input

break

lst.append(tuple(s))

lst.sort(key= lambda x:(x[0],x[1],x[2]))

print(lst)

Question 20:

Define a class with a generator which can iterate the numbers, which are divisible by 7, between a given range 0 and n.

解法一

class Test:

def generator(self,n):

return [i for i in range(n) if i%7==0]

n = int(input())

num = Test()

lst = num.generator(n)

print(lst)

源代碼下載

這十道題的代碼在我的github上，如果大家想看一下每道題的輸出結果，可以點擊以下鏈接下載：

我的運行環境Python 3.6+,如果你用的是Python 2.7版本，絕大多數不同就體現在以下3點：

raw_input()在Python3中是input()

print需要加括號

fstring可以換成.format(),或者%s，%d

謝謝大家，我們下期見！希望各位朋友不要吝嗇，把每道題的更高效的解法寫在評論里，我們一起進步！！！

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