函數功能：統計字符串中空格的個數.?

#include <stdio.h> #include <string.h> int count_spaces(char *p,int n) { int i = 0; int count = 0; while((*p != '\0') && ((*p == ' ')?(++ count):(count))){if(*p == ' ')printf("yes");printf("%d 's value is:%c",i,*p);++ p;} return count;} #define LEN 100 int main() { char p[LEN + 1] = "ad sd sdfa sa "; int n = count_spaces(p,sizeof(p) / sizeof(p[0])); printf("%d\n",n);return 0; }

上述錯誤在于：當while的條件為假一次，那么while就徹底停止了,也就是當條件表達式的返回值為假一次，那么while將會停止。鬼知道條件表達式返回個什么東西。

更改后：

#include <stdio.h> #include <string.h> int count_spaces(char *p,int n) { int count = 0;while(*p != '\0'){if(*p == ' ') ++ count;++ p;} return count;} #define LEN 100 int main() { char p[LEN + 1] = "ad sd sdfa sa "; int n = count_spaces(p,sizeof(p) / sizeof(p[0])); printf("%d\n",n);return 0; } ~

運行結果：５

方法２：

#include <stdio.h> #include <string.h> int count_spaces(char *p,int n) { int count = 0,i = 0;while(p[i] != '\0'){if(p[i] == ' ') ++ count;++ i;} return count;} #define LEN 100 int main() { char p[LEN + 1] = "ad sd sdfa sa "; int n = count_spaces(p,sizeof(p) / sizeof(p[0])); printf("%d\n",n);return 0; } ~

運行結果：５

方法3：

#include <stdio.h> #include <string.h> int count_spaces(char *p,int n) { int count = 0;while(*p){ if(*p == ' ') count ++;++p;} return count;} #define LEN 100 int main() { char p[LEN + 1] = "ad sd sdfa sa "; int n = count_spaces(p,sizeof(p) / sizeof(p[0])); printf("%d\n",n);return 0; } ~

運行結果：5? ?

總結

以上是生活随笔為你收集整理的问题：c语言简单的循环和字符串，错在哪里了？结果怎么是0（已解决）的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。