這是我使用的代碼。最后，我不得不重新調(diào)整我的數(shù)據(jù)幀，但只是為了更好地閱讀。我認(rèn)為我的代碼有很多可能的改進(jìn)，但是我很高興我的代碼行為足夠好地滿足我的需要。在import cv2

import numpy as np

import pandas as pd

img = cv2.imread('full_snap.png')

"""

some of my blue pixels

R: between 98 and 128

G: between 176 and 211

B: between 255

h: between 210 and 200

s: between 100 and 48

v: between 68 and 100

hsv/2 in opencv and opencv uses BGR not RGB

"""

blue_MIN = np.array([255, 176, 98])

blue_MAX = np.array([255, 211, 128])

"""

https://pythonprogramming.net/color-filter-python-opencv-tutorial/

"""

# find the blue pixels and save it in frame_threshed

frame_threshed = cv2.inRange(img, blue_MIN, blue_MAX)

# find contours in the thresholded image

cnts = cv2.findContours(frame_threshed.copy(), cv2.RETR_EXTERNAL,

cv2.CHAIN_APPROX_SIMPLE)

cnts = cnts[0] if imutils.is_cv2() else cnts[1]

#print("cnts", cnts)

i = len(cnts)

print("i", i)

# we know we're gonna have x rows of data, where x is the product of

# board_width * board_height

numberOfRows = 81

# check if the length of cnts are euqal to the number of rows/ number of tiles

# then go further

# TODO

# create x,y data

# df = pd.DataFrame(index=np.arange(numberOfRows, 0), columns=('x', 'y'))

d = []

print("d", d)

print(type(d))

for c in cnts:

# compute the center of the contour

M = cv2.moments(c)

cX = int(M["m10"] / M["m00"])

cY = int(M["m01"] / M["m00"])

# fill the data with the coords

d.append({'tilenumber': i, 'X-Value': cX, 'Y-Value': cY})

# decrease i to go backwards, because tile number 81 is the first contour

i-=1

# draw the center of the shape on the image

cv2.circle(img, (cX, cY), 1, (255, 255, 255), -1)

df = pd.DataFrame(d)

# only for debugging

print("x,y dataframe", df)

cv2.imshow("Image_with_contours",img)

# Destroys all of the HighGUI windows.

cv2.destroyAllWindows()

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