轉(zhuǎn)載自：http://blog.csdn.net/jianggujin/article/details/72833711 如要轉(zhuǎn)載請寫明原創(chuàng)地址

• Java實現(xiàn)
• Javascript實現(xiàn)
• MySQL實現(xiàn)

最近在做與地圖相關(guān)的應(yīng)用，使用了高德地圖，研究了下高德地圖計算兩坐標(biāo)距離的方法，官網(wǎng)上提供的開發(fā)包中有相關(guān)的方法，但是我的產(chǎn)品中比較特殊，無法直接使用提供的方法，所以就自己封裝了相關(guān)計算方法，供大家參考。

Java實現(xiàn)

首先定義一個用于存儲經(jīng)緯度的類，這里起個名字叫：LngLat

package amap;import java.text.DecimalFormat; import java.text.DecimalFormatSymbols; import java.util.Locale;/*** 存儲經(jīng)緯度坐標(biāo)值的類，單位角度* * @author jianggujin**/ public final class LngLat implements Cloneable {/*** 緯度 (垂直方向)*/public final double latitude;/*** 經(jīng)度 (水平方向)*/public final double longitude;/*** 格式化*/private static DecimalFormat format = new DecimalFormat("0.000000", new DecimalFormatSymbols(Locale.US));/*** 使用傳入的經(jīng)緯度構(gòu)造LatLng 對象，一對經(jīng)緯度值代表地球上一個地點。* * @param longitude* 地點的經(jīng)度，在-180 與180 之間的double 型數(shù)值。* @param latitude* 地點的緯度，在-90 與90 之間的double 型數(shù)值。*/public LngLat(double longitude, double latitude){this(longitude, latitude, true);}/*** 使用傳入的經(jīng)緯度構(gòu)造LatLng 對象，一對經(jīng)緯度值代表地球上一個地點* * @param longitude* 地點的經(jīng)度，在-180 與180 之間的double 型數(shù)值。* * @param latitude* 地點的緯度，在-90 與90 之間的double 型數(shù)值。* @param isCheck* 是否需要檢查經(jīng)緯度的合理性，建議填寫true*/public LngLat(double longitude, double latitude, boolean isCheck){if (isCheck){if ((-180.0D <= longitude) && (longitude < 180.0D))this.longitude = parse(longitude);else{throw new IllegalArgumentException("the longitude range [-180, 180].");// this.longitude = parse(((longitude - 180.0D) % 360.0D + 360.0D) %// 360.0D - 180.0D);}if ((latitude < -90.0D) || (latitude > 90.0D)){throw new IllegalArgumentException("the latitude range [-90, 90].");}this.latitude = latitude;// this.latitude = parse(Math.max(-90.0D, Math.min(90.0D, latitude)));}else{this.latitude = latitude;this.longitude = longitude;}}/*** 解析* * @param d* @return*/private static double parse(double d){return Double.parseDouble(format.format(d));}public LngLat clone(){return new LngLat(this.latitude, this.longitude);}@Overridepublic int hashCode(){final int prime = 31;int result = 1;long temp;temp = Double.doubleToLongBits(latitude);result = prime * result + (int) (temp ^ (temp >>> 32));temp = Double.doubleToLongBits(longitude);result = prime * result + (int) (temp ^ (temp >>> 32));return result;}@Overridepublic boolean equals(Object obj){if (this == obj)return true;if (obj == null)return false;if (getClass() != obj.getClass())return false;LngLat other = (LngLat) obj;if (Double.doubleToLongBits(latitude) != Double.doubleToLongBits(other.latitude))return false;if (Double.doubleToLongBits(longitude) != Double.doubleToLongBits(other.longitude))return false;return true;}public String toString(){return "lat/lng: (" + this.latitude + "," + this.longitude + ")";} }

計算工具類如下：

package amap;/*** 高德地圖工具* * @author jianggujin**/ public class AMapUtils {/*** 根據(jù)用戶的起點和終點經(jīng)緯度計算兩點間距離，此距離為相對較短的距離，單位米。* * @param start* 起點的坐標(biāo)* @param end* 終點的坐標(biāo)* @return*/public static double calculateLineDistance(LngLat start, LngLat end){if ((start == null) || (end == null)){throw new IllegalArgumentException("非法坐標(biāo)值，不能為null");}double d1 = 0.01745329251994329D;double d2 = start.longitude;double d3 = start.latitude;double d4 = end.longitude;double d5 = end.latitude;d2 *= d1;d3 *= d1;d4 *= d1;d5 *= d1;double d6 = Math.sin(d2);double d7 = Math.sin(d3);double d8 = Math.cos(d2);double d9 = Math.cos(d3);double d10 = Math.sin(d4);double d11 = Math.sin(d5);double d12 = Math.cos(d4);double d13 = Math.cos(d5);double[] arrayOfDouble1 = new double[3];double[] arrayOfDouble2 = new double[3];arrayOfDouble1[0] = (d9 * d8);arrayOfDouble1[1] = (d9 * d6);arrayOfDouble1[2] = d7;arrayOfDouble2[0] = (d13 * d12);arrayOfDouble2[1] = (d13 * d10);arrayOfDouble2[2] = d11;double d14 = Math.sqrt((arrayOfDouble1[0] - arrayOfDouble2[0]) * (arrayOfDouble1[0] - arrayOfDouble2[0])+ (arrayOfDouble1[1] - arrayOfDouble2[1]) * (arrayOfDouble1[1] - arrayOfDouble2[1])+ (arrayOfDouble1[2] - arrayOfDouble2[2]) * (arrayOfDouble1[2] - arrayOfDouble2[2]));return (Math.asin(d14 / 2.0D) * 12742001.579854401D);} }

最后邊寫一段測試代碼測試一下：

package test;import org.junit.Test;import amap.AMapUtils; import amap.LngLat;public class AMapTest {@Testpublic void Test(){LngLat start = new LngLat(116.368904, 39.923423);LngLat end = new LngLat(116.387271, 39.922501);System.err.println(AMapUtils.calculateLineDistance(start, end));} }

運行結(jié)果為：1569.6213922679392，官網(wǎng)的javascript API示例結(jié)果如圖：

結(jié)果雖然有一點誤差，但是這hi在可接受范圍內(nèi)的。

Javascript實現(xiàn)

同樣的算法，將其轉(zhuǎn)換成JS的寫法，完整的代碼如下：

<!DOCTYPE html> <html><head><meta charset="utf-8" /><title></title><script type="text/javascript" src="js/ajax.js"></script><script>/*** 存儲經(jīng)緯度* @param {Object} longitude* @param {Object} latitude*/function LngLat(longitude, latitude) {this.longitude = longitude;this.latitude = latitude;}function calculateLineDistance(start, end) {var d1 = 0.01745329251994329;var d2 = start.longitude;var d3 = start.latitude;var d4 = end.longitude;var d5 = end.latitude;d2 *= d1;d3 *= d1;d4 *= d1;d5 *= d1;var d6 = Math.sin(d2);var d7 = Math.sin(d3);var d8 = Math.cos(d2);var d9 = Math.cos(d3);var d10 = Math.sin(d4);var d11 = Math.sin(d5);var d12 = Math.cos(d4);var d13 = Math.cos(d5);var arrayOfDouble1 = [];var arrayOfDouble2 = [];arrayOfDouble1.push(d9 * d8);arrayOfDouble1.push(d9 * d6);arrayOfDouble1.push(d7);arrayOfDouble2.push(d13 * d12);arrayOfDouble2.push(d13 * d10);arrayOfDouble2.push(d11);var d14 = Math.sqrt((arrayOfDouble1[0] - arrayOfDouble2[0]) * (arrayOfDouble1[0] - arrayOfDouble2[0]) +(arrayOfDouble1[1] - arrayOfDouble2[1]) * (arrayOfDouble1[1] - arrayOfDouble2[1]) +(arrayOfDouble1[2] - arrayOfDouble2[2]) * (arrayOfDouble1[2] - arrayOfDouble2[2]));return(Math.asin(d14 / 2.0) * 12742001.579854401);}var start = new LngLat(116.368904, 39.923423);var end = new LngLat(116.387271, 39.922501);</script></head><body><script>document.write(calculateLineDistance(start, end));</script></body> </html>

MySQL實現(xiàn)

DELIMITER $$ CREATE FUNCTION `calculateLineDistance`(startLng double, startLat double, endLng double, endLat double) RETURNS double BEGIN declare d2 DOUBLE; declare d3 DOUBLE; declare d4 DOUBLE; declare d5 DOUBLE; declare d6 DOUBLE; declare d7 DOUBLE; declare d8 DOUBLE; declare d9 DOUBLE; declare d10 DOUBLE; declare d11 DOUBLE; declare d12 DOUBLE; declare d13 DOUBLE; declare d14 DOUBLE; declare arrayOfDouble10 DOUBLE; declare arrayOfDouble11 DOUBLE; declare arrayOfDouble12 DOUBLe; declare arrayOfDouble20 DOUBLE; declare arrayOfDouble21 DOUBLE; declare arrayOfDouble22 DOUBLE; set d2 = startLng * 0.01745329251994329; set d3 = startLat * 0.01745329251994329; set d4 = endLng * 0.01745329251994329; set d5 = endLat * 0.01745329251994329; set d6 = sin(d2); set d7 = sin(d3); set d8 = cos(d2); set d9 = cos(d3); set d10 = sin(d4); set d11 = sin(d5); set d12 = cos(d4); set d13 = cos(d5); set arrayOfDouble10 = (d9 * d8); set arrayOfDouble11 = (d9 * d6); set arrayOfDouble12 = d7; set arrayOfDouble20 = (d13 * d12); set arrayOfDouble21 = (d13 * d10); set arrayOfDouble22 = d11; set d14 = sqrt((arrayOfDouble10 - arrayOfDouble20) * (arrayOfDouble10 - arrayOfDouble20)+ (arrayOfDouble11 - arrayOfDouble21) * (arrayOfDouble11 - arrayOfDouble21)+ (arrayOfDouble12 - arrayOfDouble22) * (arrayOfDouble12 - arrayOfDouble22)); return (asin(d14 / 2.0) * 12742001.579854401); END $$ DELIMITER ;

總結(jié)

以上是生活随笔為你收集整理的高德地图计算两坐标之间距离的全部內(nèi)容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網(wǎng)站內(nèi)容還不錯，歡迎將生活随笔推薦給好友。