輸入a?b?c?d?e以及它們對(duì)應(yīng)的數(shù)字
比如
a-->1?2?3?
b-->2?3
c-->1
d-->3?4?5
e-->1?3?5
輸出a?b?c?d?e的可用組合，a?b?c?d?e不重復(fù)，如
a-->2
b-->3
c-->1
d-->4
e-->5

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using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks;namespace ConsoleApplication1 {class Program{static void Main(string[] args){var dict = new Dictionary<char, List<int>>(){{ 'a', new List<int> { 1, 2, 3 } },{ 'b', new List<int> { 2, 3 } },{ 'c', new List<int> { 1 } },{ 'd', new List<int> { 3, 4, 5 } },{ 'e', new List<int> { 1, 3, 5 } }};foo(dict, new Dictionary<char, int>());}static void foo(Dictionary<char, List<int>> data, Dictionary<char, int> pre){if (data.Count == 0){Console.WriteLine("found:");foreach (var item in pre.OrderBy(x => x.Key))Console.WriteLine("{0} - {1}", item.Key, item.Value);return;}var first = data.OrderBy(x => x.Value.Count()).First();foreach (var item in first.Value){foo(data.OrderBy(x => x.Value.Count()).Skip(1).ToDictionary(x => x.Key, x => x.Value.Except(new int[] { item }).ToList()), pre.Cast<KeyValuePair<char, int>>().Concat(new KeyValuePair<char, int>[] { new KeyValuePair<char, int>(first.Key, item) }).ToDictionary(x => x.Key, x => x.Value));}}} }

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