?以下為通過經緯度坐標值求取兩點間距離的算法，計算通過c++實現，在計算過程中已考慮到地球的弧度，經驗證算法正確可行，精度為0.001米。

#include "pch.h" #include <iostream> #define _USE_MATH_DEFINES #include <math.h> #include <iomanip>using namespace std;double Earth_Radius = 6378.137; double OutDistance = 0; double OutAzimuth = 0;double Angle2Rad(double Angle) {return Angle * M_PI / 180.0; }double Rad2Angle(double Rad) {return Rad * 180.0 / M_PI; }/* Lat:緯度 Lng:經度 */ void GetDistance(double Lat1, double Lng1, double Lat2, double Lng2,double *P_OutDistance,double *P_OutAzimuth) {double RadLat1 = Angle2Rad(Lat1);double RadLat2 = Angle2Rad(Lat2);double RadLng1 = Angle2Rad(Lng1);double RadLng2 = Angle2Rad(Lng2);double Lat_Dif = RadLat1 - RadLat2;double Lng_Dif = RadLng1 - RadLng2;/**----------- Calculate Distance-----------**/double Distance = 2 * asin(sqrt(pow(sin(Lat_Dif / 2.0), 2)+ cos(RadLat1) * cos(RadLat2)* pow(sin(Lng_Dif / 2.0), 2)));Distance = Distance * Earth_Radius;//Distance = round(Distance * 10000) / 10000;Distance = Distance * 1000;/**----------- Calculate Azimuth-----------**/double Azimuth = sin(RadLat1) * sin(RadLat2)+ cos(RadLat1) * cos(RadLat2) * cos(RadLng2- RadLng1);Azimuth = sqrt(1 - pow(Azimuth, 2));Azimuth = cos(RadLat2) * sin(RadLng2 - RadLng1) / Azimuth; Azimuth = Rad2Angle(asin(Azimuth));*P_OutDistance = Distance;*P_OutAzimuth = Azimuth; }void main(void) {GetDistance(0, 0, 0, 0,&OutDistance,&OutAzimuth);cout << "Distance = " << setprecision(7) << OutDistance << endl;cout << "Azimuth = " << setprecision(4) << OutAzimuth << endl;getchar(); }

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