將c串從a，b串中刪去后求最長公子列 ?直接暴會超時

#include <cstdio> #include <cstdlib> #include <algorithm> #include <cstring> using namespace std;char a[1010],b[1010],c[1010]; int dp1[1010][1010],dp2[1010][1010]; int aa[1010],bb[1010]; int main() {int t, ca = 1;scanf("%d",&t);while(t--){scanf("%s%s%s",a,b,c);memset(dp1, 0, sizeof(dp1));memset(dp2, 0 , sizeof(dp2));int len1 = strlen(a), len2 = strlen(b), len3 = strlen(c);for(int i = 1; i <= len1; i++)for(int j = 1; j <= len2; j++)if(a[i-1] == b[j-1])dp1[i][j] = dp1[i-1][j-1]+1;elsedp1[i][j] = max(dp1[i-1][j], dp1[i][j-1]);for(int i = len1; i >= 1; i--)for(int j = len2; j >= 1; j--)if(a[i-1] == b[j-1])dp2[i][j] = dp2[i+1][j+1]+1;elsedp2[i][j] = max(dp2[i+1][j], dp2[i][j+1]);for(int i = 1; i <= len1; i++){int u = 0, j;for(j = i; j <= len1; j++){if(c[u] == a[j-1]) u++;if(u == len3) break;}if(j <= len1) aa[i] = j;else aa[i] = 0;}for(int i = 1; i <= len2; i++){int u = 0, j;for(j = i; j <= len2; j++){if(c[u] == b[j-1]) u++;if(u == len3) break;}if(j <= len2) bb[i] = j;else bb[i] = 0;}int _max = 0;for(int i = 1; i <= len1; i++)for(int j = 1; j <= len2; j++)if(aa[i] && bb[j])_max = max(_max, dp1[i-1][j-1]+dp2[aa[i]+1][bb[j]+1]);printf("Case #%d: %d\n",ca++,_max+len3);}return 0; }
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轉載于:https://www.cnblogs.com/avema/p/3774291.html

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