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2路由策略_route-map(执行路由策略)

發(fā)布時(shí)間:2023/12/20 编程问答 26 豆豆
生活随笔 收集整理的這篇文章主要介紹了 2路由策略_route-map(执行路由策略) 小編覺得挺不錯(cuò)的,現(xiàn)在分享給大家,幫大家做個(gè)參考.
拓?fù)鋱D: 配置參數(shù): R1

access-list 10 permit 192.168.5.0 0.0.0.255?//配置匹配的流量 route-map ospf permit 10?//創(chuàng)建一個(gè)路由圖配置要匹配的流量

match ip address 10??//關(guān)聯(lián)要匹配的流量 set metric 1?//設(shè)置匹配流量的度量值為1 route-map ospf permit 20?//接著用上面的路由圖,配置序號為20,設(shè)置其它的流量

set metric 2//設(shè)置其它的流量的度量值為2 router ospf 1

redistribute rip subnets//OSPF里重發(fā)布RIP,讓R4可以學(xué)習(xí)到 network 192.168.3.0 0.0.0.255 area 0

router rip

version 2

redistribute ospf 1 route-map ospf//RIP里重發(fā)布OSPF,并應(yīng)用上面配置好的路由圖,達(dá)到?分流(兩臺設(shè)備[R1,R3]配置不同的度量值)和熱備(動態(tài)路由可以動態(tài)感知網(wǎng)絡(luò)拓?fù)涞淖兓?#xff0c;動態(tài)的將度量值小的路由裝進(jìn)路由表)的效果!!! network 192.168.1.0

no auto-summary

?

R2:

access-list 20 permit 192.168.6.0 0.0.0.255

route-map ospf permit 10

match ip address 20

set metric 1

route-map ospf permit 20

set metric 2

router ospf 1

redistribute rip subnets

network 192.168.4.0 0.0.0.255 area 0

router rip

version 2

redistribute ospf 1 route-map ospf

network 192.168.2.0

no auto-summary 測試: r5#sh ip int b Interface??????????????????IP-Address??????OK? Method Status????????????????Protocol FastEthernet0/0????????????192.168.100.2???YES NVRAM??up????????????????????up????? r5#traceroute 192.168.5.1

1 192.168.100.1 1032 msec 20 msec 4 msec

2 192.168.1.2 16 msec 8 msec 60 msec

3 192.168.3.2 32 msec 12 msec * r5#traceroute 192.168.6.1

??1 192.168.100.1 32 msec 16 msec 16 msec

??2 192.168.2.2 12 msec 28 msec 32 msec

??3 192.168.4.2 16 msec 32 msec * r5# 可以看出要去192.168.5.0的網(wǎng)絡(luò)走左邊,去192.168.6.0的網(wǎng)絡(luò)走右邊!!!

?

配置成功后路由表是這樣的: R2: R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:17, Ethernet1/1

????????????????????[120/2] via 192.168.1.2, 00:00:11, Ethernet1/0

?????192.168.5.0/32 is subnetted, 1 subnets

R???????192.168.5.1 [120/1] via 192.168.1.2, 00:00:11, Ethernet1/0

?????192.168.6.0/32 is subnetted, 1 subnets

R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:17, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0

C????192.168.2.0/24 is directly connected, Ethernet1/1

C????192.168.100.0/24 is directly connected, FastEthernet0/0

R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:17, Ethernet1/1

????????????????????[120/2] via 192.168.1.2, 00:00:11, Ethernet1/0 可以看出,R2通過R1學(xué)習(xí)到192.168.5.0并且為1跳,通過R3學(xué)習(xí)到192.168.6.0并且為1跳。 現(xiàn)在來測試一下,將R1E0/0(連著R4的接口)down掉,看看會發(fā)現(xiàn)什么現(xiàn)象: R1:

r1(config)#int e0/0

r1(config-if)#sh

r1(config-if)#shutdown R2:

r2#sh ip rou

R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

?????192.168.5.0/32 is subnetted, 1 subnets

R???????192.168.5.1 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

?????192.168.6.0/32 is subnetted, 1 subnets

R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:12, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0

C????192.168.2.0/24 is directly connected, Ethernet1/1

C????192.168.100.0/24 is directly connected, FastEthernet0/0

R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

r2# 可以看出R2是通過R3學(xué)習(xí)到的192.168.5.0的路由的,它的跳數(shù)為2R5要去192.168.5.0的路由要走右邊,因?yàn)樽筮叺?/span>R1的上連端口down掉了。這樣達(dá)到了熱備的效果!!!

?

現(xiàn)在把R1E0/0再開啟,看看會是什么效果: R1: r1(config)#int e0/0


r1(config-if)#no shutdown R2: r2#??SH IP ROU R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:05, Ethernet1/1 [120/2] via 192.168.1.2, 00:00:25, Ethernet1/0 192.168.5.0/32 is subnetted, 1 subnets R???????192.168.5.1 [120/1] via 192.168.1.2, 00:00:25, Ethernet1/0

192.168.6.0/32 is subnetted, 1 subnets R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:05, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0 C????192.168.2.0/24 is directly connected, Ethernet1/1 C????192.168.100.0/24 is directly connected, FastEthernet0/0 R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:05, Ethernet1/1 [120/2] via 192.168.1.2, 00:00:25, Ethernet1/0 r2# 可以看出,R2通過動態(tài)路由感知到網(wǎng)絡(luò)拓?fù)涞淖兓?#xff0c;動態(tài)地學(xué)習(xí)到了度量值優(yōu)的路由,然后入進(jìn)入路由表里!!!
? ? ? 本文轉(zhuǎn)自810105851 51CTO博客,原文鏈接:http://blog.51cto.com/4708948/1130037,如需轉(zhuǎn)載請自行聯(lián)系原作者




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