您可以使用

Array#map方法生成新數組(假設兩個數組的順序相同).

var lat = [{key:"2017-09-20T11:51:32.000Z", value:50.7825333},{key:"2017-09-20T11:51:33.000Z", value:50.7826}];

var lon = [{key:"2017-09-20T11:51:32.000Z", value:-1.3075833},{key:"2017-09-20T11:51:33.000Z", value:-1.3076}];

var res = lat

// iterate over the first array

.map(function(o, i) {

// generate the array element

// where get values from element and

// get value from second array using

// the index

return {

time: o.key,

lat: o.value,

lon: lon[i].value

}

})

console.log(res);

// with ES6 arrow function

var res1 = lat.map((o, i) => ({time: o.key, lat: o.value, lon: lon[i].value}))

console.log(res1);

僅供參考：如果相關數組元素的順序不同,則需要通過比較時間值(可以使用Array#find方法)從第二個數組中獲取元素,或者生成一個哈希映射來映射對象.

var lat = [{key:"2017-09-20T11:51:32.000Z", value:50.7825333},{key:"2017-09-20T11:51:33.000Z", value:50.7826}];

var lon = [{key:"2017-09-20T11:51:32.000Z", value:-1.3075833},{key:"2017-09-20T11:51:33.000Z", value:-1.3076}];

var res = lat

.map(function(o) {

return {

time: o.key,

lat: o.value,

// get object by using find method

lon: lon.find(function(o1) {

return o1.key === o.key;

}).value

}

})

console.log(res);

// with ES6 arrow function

var res1 = lat.map(o => ({

time: o.key,

lat: o.value,

lon: lon.find(o1 => o1.key === o.key).value

}))

console.log(res1);

使用hashmap進行引用的更有效方法：

var lat = [{key:"2017-09-20T11:51:32.000Z", value:50.7825333},{key:"2017-09-20T11:51:33.000Z", value:50.7826}];

var lon = [{key:"2017-09-20T11:51:32.000Z", value:-1.3075833},{key:"2017-09-20T11:51:33.000Z", value:-1.3076}];

// generate reference hashmap for getting

// value using the datetime string

var ref = lon.reduce(function(obj, o) {

// set reference

obj[o.key] = o.value;

// return the reference object

return obj;

// set initial value as an empty object

}, {});

var res = lat

.map(function(o) {

return {

time: o.key,

lat: o.value,

// get value from generated reference object

lon: ref[o.key]

}

})

console.log(res);

總結

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