1、實(shí)現(xiàn)方式，使用while循環(huán)，比較low，200w條數(shù)據(jù) 2s

public function getMany ($startNum, $count) {$num = $startNum;$codes[] = $startNum;for($i=1;$i<=$count;$i++){$num1 = random_int(1,9);while($num == $num1) {$num1 = random_int(1,9);}$num = $num1;$startNum += $num;$codes[] = $startNum;}return $codes; }

2、實(shí)現(xiàn)方式，使用遞歸，把random_int替換成mt_rand，200w數(shù)據(jù)0.9s

public function getManys ($num, $count) {$codes = [];$startNum = 0;for($i = 1;$i <= $count; $i++){$num = $this->getNotRepeatNum($num, mt_rand(1, 9));$startNum += $num;$codes[] = $startNum;}return $codes; }public function getNotRepeatNum($startNum, $endNum) {if($startNum == $endNum) {return $this->getNotRepeatNum($startNum, mt_rand(1, 9));}return $endNum; }

3、實(shí)現(xiàn)方式，上次使用的數(shù)據(jù)下次不使用，把random_int替換成mt_rand，200w數(shù)據(jù)0.7s

public function getManys ($startNum, $count) {$codes = [];$num = [1,2,3,4,5,6,7,8,9];$lastNum = 0;for($i=1;$i<=$count;$i++){if($lastNum == 0) {$startNum += $num[mt_rand(0, 8)];} else {$diff = array_diff($num, [$lastNum]);$startNum += $diff[mt_rand(0, 7)];}$codes[] = $startNum;}return $codes; }

總結(jié)

以上是生活随笔為你收集整理的订单编号，递增且不连续（php版）的全部?jī)?nèi)容，希望文章能夠幫你解決所遇到的問(wèn)題。

如果覺(jué)得生活随笔網(wǎng)站內(nèi)容還不錯(cuò)，歡迎將生活随笔推薦給好友。