nhibernate学习之集合组合依赖
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nhibernate学习之集合组合依赖
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1.學習目標
?? 還是學習compenent的用法,上節實現了簡單字段的組合,這節中將討論兩個問題:1.依賴對象有一個指向容器對象的引用。2。集合依賴
2.開發環境和必要準備
?? 開發環境為:windows 2003,Visual studio .Net 2005,Sql server 2005 developer edition
? 必要準備:學習前六篇nhibernate學習系列Nhibernate學習之起步篇-1? ,Nhibernate學習起步之many-to-one篇 ,Nhibernate學習之many-to-many篇 ,nhibernate學習之三級聯(Ternary Associations)篇 ,Nhibernate學習之性能改善1 ,nhibernate性能之二級緩存篇 ,nhibernate學習之簡單組合的映射
3.通過parent為依賴組合對象映射一個指向容器對象的引用
? CompositeUser.cs?
public?class?CompositeUser
????{
????????int?_uid;
????????UserName?_name;
????????public?int?Uid
????????{
????????????get
????????????{
????????????????return?_uid;
????????????}
????????????set
????????????{
????????????????_uid?=?value;
????????????}
????????}
????????public?UserName?Name
????????{
????????????get
????????????{
????????????????return?_name;
????????????}
????????????set
????????????{
????????????????_name?=?value;
????????????}
????????}
????} ? UserName.cs
?public?class?UserName
????{
????????private?string?_firstName;
????????private?string?_lastName;
????????CompositeUser?_user;
????????public?string?FirstName
????????{
????????????get
????????????{
????????????????return?_firstName;
????????????}
????????????set
????????????{
????????????????_firstName=value;
????????????}
????????}
????????public?string?LastName
????????{
????????????get
????????????{
????????????????return?_lastName;
????????????}
????????????set
????????????{
????????????????_lastName?=?value;
????????????}
????????}
????????public?CompositeUser?User
????????{
????????????get
????????????{
????????????????return?_user;
????????????}
????????????set
????????????{
????????????????_user?=?value;
????????????}
????????}
????} 映射文件:CompositeUser.hbm.xml
<?xml?version="1.0"?encoding="utf-8"??>
<hibernate-mapping?xmlns="urn:nhibernate-mapping-2.2">
????<class?name="NhibernateSample1.CompositeUser,NhibernateSample1"?table="CompositeUser"?lazy="false">
????????<id?name="Uid"?column="Uid"?unsaved-value="0">
????????????<generator?class="native"?/>
????????</id>
????????<component?name="Name"?class="NhibernateSample1.UserName,NhibernateSample1">
????????????<parent?name="User"></parent>
????????????<property?name="FirstName"?column="FirstName"></property>
????????????<property?name="LastName"?column="LastName"></property>
????????</component>
????</class>
</hibernate-mapping> 注意parent是指向容器對象的引用
加載一個CompositeUser對象,結果如圖
4. 集合組合依賴
Composite.cs
public?class?CompositeUser
????{
????????int?_uid;
????????UserName?_name;
????????ISet?_userNames?=?new?HashedSet();
????????DateTime?_birthDay?=?DateTime.Now;
????????public?int?Uid
????????{
????????????get
????????????{
????????????????return?_uid;
????????????}
????????????set
????????????{
????????????????_uid?=?value;
????????????}
????????}
????????public?ISet?UserNames
????????{
????????????get
????????????{
????????????????return?_userNames;
????????????}
????????????set
????????????{
????????????????_userNames?=?value;
????????????}
????????}
????????public?DateTime?BirthDay
????????{
????????????get
????????????{
????????????????return?_birthDay;
????????????}
????????????set
????????????{
????????????????_birthDay?=?value;
????????????}
????????}
????} UserName.cs
public?class?UserName
????{
????????private?string?_firstName;
????????private?string?_lastName;
????????CompositeUser?_user;
????????public?string?FirstName
????????{
????????????get
????????????{
????????????????return?_firstName;
????????????}
????????????set
????????????{
????????????????_firstName=value;
????????????}
????????}
????????public?string?LastName
????????{
????????????get
????????????{
????????????????return?_lastName;
????????????}
????????????set
????????????{
????????????????_lastName?=?value;
????????????}
????????}
????????public?CompositeUser?User
????????{
????????????get
????????????{
????????????????return?_user;
????????????}
????????????set
????????????{
????????????????_user?=?value;
????????????}
????????}
????} 映射文件CompositeUser.hbm.xml
<?xml?version="1.0"?encoding="utf-8"??>
<hibernate-mapping?xmlns="urn:nhibernate-mapping-2.2">
????<class?name="NhibernateSample1.CompositeUser,NhibernateSample1"?table="CompositeUser"?lazy="false">
????????<id?name="Uid"?column="Uid"?unsaved-value="0">
????????????<generator?class="native"?/>
????????</id>
????????<set?name="UserNames"?table="UserNames"?lazy="true">
????????????<key?column="Uid"/>
????????????<composite-element??class="NhibernateSample1.UserName,NhibernateSample1">
????????????????<property?name="FirstName"?column="FirstName"></property>
????????????????<property?name="LastName"?column="LastName"></property>
????????????</composite-element?>
????????</set>
????????<property?name="BirthDay"?type="DateTime"></property>
????</class>
</hibernate-mapping> 注意:Composite可以包含集合也可以不包含集合,上面這樣的配置就不包括集合,映射的屬性可以選擇為List,map,bag,idbag
運行添加一個Composite的測試代碼,會在數據庫中建立兩個數據表 CompositeUser和UserNames
效果圖
?
?? 還是學習compenent的用法,上節實現了簡單字段的組合,這節中將討論兩個問題:1.依賴對象有一個指向容器對象的引用。2。集合依賴
2.開發環境和必要準備
?? 開發環境為:windows 2003,Visual studio .Net 2005,Sql server 2005 developer edition
? 必要準備:學習前六篇nhibernate學習系列Nhibernate學習之起步篇-1? ,Nhibernate學習起步之many-to-one篇 ,Nhibernate學習之many-to-many篇 ,nhibernate學習之三級聯(Ternary Associations)篇 ,Nhibernate學習之性能改善1 ,nhibernate性能之二級緩存篇 ,nhibernate學習之簡單組合的映射
3.通過parent為依賴組合對象映射一個指向容器對象的引用
? CompositeUser.cs?
public?class?CompositeUser
????{
????????int?_uid;
????????UserName?_name;
????????public?int?Uid
????????{
????????????get
????????????{
????????????????return?_uid;
????????????}
????????????set
????????????{
????????????????_uid?=?value;
????????????}
????????}
????????public?UserName?Name
????????{
????????????get
????????????{
????????????????return?_name;
????????????}
????????????set
????????????{
????????????????_name?=?value;
????????????}
????????}
????} ? UserName.cs
?public?class?UserName
????{
????????private?string?_firstName;
????????private?string?_lastName;
????????CompositeUser?_user;
????????public?string?FirstName
????????{
????????????get
????????????{
????????????????return?_firstName;
????????????}
????????????set
????????????{
????????????????_firstName=value;
????????????}
????????}
????????public?string?LastName
????????{
????????????get
????????????{
????????????????return?_lastName;
????????????}
????????????set
????????????{
????????????????_lastName?=?value;
????????????}
????????}
????????public?CompositeUser?User
????????{
????????????get
????????????{
????????????????return?_user;
????????????}
????????????set
????????????{
????????????????_user?=?value;
????????????}
????????}
????} 映射文件:CompositeUser.hbm.xml
<?xml?version="1.0"?encoding="utf-8"??>
<hibernate-mapping?xmlns="urn:nhibernate-mapping-2.2">
????<class?name="NhibernateSample1.CompositeUser,NhibernateSample1"?table="CompositeUser"?lazy="false">
????????<id?name="Uid"?column="Uid"?unsaved-value="0">
????????????<generator?class="native"?/>
????????</id>
????????<component?name="Name"?class="NhibernateSample1.UserName,NhibernateSample1">
????????????<parent?name="User"></parent>
????????????<property?name="FirstName"?column="FirstName"></property>
????????????<property?name="LastName"?column="LastName"></property>
????????</component>
????</class>
</hibernate-mapping> 注意parent是指向容器對象的引用
加載一個CompositeUser對象,結果如圖
4. 集合組合依賴
Composite.cs
public?class?CompositeUser
????{
????????int?_uid;
????????UserName?_name;
????????ISet?_userNames?=?new?HashedSet();
????????DateTime?_birthDay?=?DateTime.Now;
????????public?int?Uid
????????{
????????????get
????????????{
????????????????return?_uid;
????????????}
????????????set
????????????{
????????????????_uid?=?value;
????????????}
????????}
????????public?ISet?UserNames
????????{
????????????get
????????????{
????????????????return?_userNames;
????????????}
????????????set
????????????{
????????????????_userNames?=?value;
????????????}
????????}
????????public?DateTime?BirthDay
????????{
????????????get
????????????{
????????????????return?_birthDay;
????????????}
????????????set
????????????{
????????????????_birthDay?=?value;
????????????}
????????}
????} UserName.cs
public?class?UserName
????{
????????private?string?_firstName;
????????private?string?_lastName;
????????CompositeUser?_user;
????????public?string?FirstName
????????{
????????????get
????????????{
????????????????return?_firstName;
????????????}
????????????set
????????????{
????????????????_firstName=value;
????????????}
????????}
????????public?string?LastName
????????{
????????????get
????????????{
????????????????return?_lastName;
????????????}
????????????set
????????????{
????????????????_lastName?=?value;
????????????}
????????}
????????public?CompositeUser?User
????????{
????????????get
????????????{
????????????????return?_user;
????????????}
????????????set
????????????{
????????????????_user?=?value;
????????????}
????????}
????} 映射文件CompositeUser.hbm.xml
<?xml?version="1.0"?encoding="utf-8"??>
<hibernate-mapping?xmlns="urn:nhibernate-mapping-2.2">
????<class?name="NhibernateSample1.CompositeUser,NhibernateSample1"?table="CompositeUser"?lazy="false">
????????<id?name="Uid"?column="Uid"?unsaved-value="0">
????????????<generator?class="native"?/>
????????</id>
????????<set?name="UserNames"?table="UserNames"?lazy="true">
????????????<key?column="Uid"/>
????????????<composite-element??class="NhibernateSample1.UserName,NhibernateSample1">
????????????????<property?name="FirstName"?column="FirstName"></property>
????????????????<property?name="LastName"?column="LastName"></property>
????????????</composite-element?>
????????</set>
????????<property?name="BirthDay"?type="DateTime"></property>
????</class>
</hibernate-mapping> 注意:Composite可以包含集合也可以不包含集合,上面這樣的配置就不包括集合,映射的屬性可以選擇為List,map,bag,idbag
運行添加一個Composite的測試代碼,會在數據庫中建立兩個數據表 CompositeUser和UserNames
效果圖
?
轉載于:https://www.cnblogs.com/wangzhanjianshe/archive/2008/02/21/2326478.html
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