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create table capacity(type int ,numbers int ,monthst INT );

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select type,
sum(case monthst when 1 then numbers else 0 end ) 一月,
sum(case monthst when 2 then numbers else 0 end ) 二月,
sum(case monthst when 3 then numbers else 0 end ) 三月,
sum(case monthst when 4 then numbers else 0 end ) 四月,
sum(case monthst when 5 then numbers else 0 end ) 五月,
sum(case monthst when 6 then numbers else 0 end ) 六月,
sum(case monthst when 7 then numbers else 0 end ) 七月,
sum(case monthst when 8 then numbers else 0 end ) 八月,
sum(case monthst when 9 then numbers else 0 end ) 九月,
sum(case monthst when 10 then numbers else 0 end ) 十月,
sum(case monthst when 11 then numbers else 0 end ) 十一月,
sum(case monthst when 12 then numbers else 0 end ) 十二月
from capacity group by type;

?按type分組，并對每月的對應type的numbers求和。

select cap.type,sum(cap.a+cap.b+cap.c) 一季度,sum(cap.d+cap.e+cap.f) 二季度,sum(cap.g+cap.h+cap.i) 三季度,sum(cap.j+cap.k+cap.l) 四季度 from(select type,sum(case monthst when 1 then numbers else 0 end ) a,sum(case monthst when 2 then numbers else 0 end ) b,sum(case monthst when 3 then numbers else 0 end ) c,sum(case monthst when 4 then numbers else 0 end ) d,sum(case monthst when 5 then numbers else 0 end ) e,sum(case monthst when 6 then numbers else 0 end ) f,sum(case monthst when 7 then numbers else 0 end ) g,sum(case monthst when 8 then numbers else 0 end ) h,sum(case monthst when 9 then numbers else 0 end ) i,sum(case monthst when 10 then numbers else 0 end ) j,sum(case monthst when 11 then numbers else 0 end ) k,sum(case monthst when 12 then numbers else 0 end ) lfrom capacity group by type) cap group by cap.type;

?再對每行多列合并求和。

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轉載于:https://www.cnblogs.com/mryangbo/p/10760796.html

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