--如何按字段刪除重復(fù)記錄

一張表里面以兩個(gè)字段為唯一字段，當(dāng)幾條記錄的這兩個(gè)字段完全相同時(shí)，需要?jiǎng)h除重復(fù)項(xiàng)，如下表
a b c d
1 2 3 4
1 5 3 5
1 2 7 9
以a、b為唯一字段，第一條和第三條的a、b完全相同，所以，需要?jiǎng)h除第一條記錄1 2 3 4 或者第三條記錄1 2 7 9
即如下結(jié)果：
a b c d
1 2 3 4
1 5 3 5
或
a b c d
1 5 3 5
1 2 7 9



CREATE TABLE Tb1(id int, [a] varchar(255), [b] varchar(255), [c] varchar(255), [d] varchar(255))
INSERT Tb1(id, [a], [b], [c], [d])
?????????? SELECT 1, '1','2','3','4'
UNION ALL? SELECT 2, '1','5','3','5'
UNION ALL? SELECT 3, '1','2','7','9'
UNION ALL? SELECT 4, '1','4','7','6'

delete Tb1 where [id] not in (select max([id]) from Tb1 group by a,b )
select * from tb1

drop table tb1

如果要同時(shí)刪除第一和第三行
即如下結(jié)果：
a b c d
1 5 3 5

語句如下：

delete m from tb t
inner join
(
select a ,b
from tb
group by a , b
having count(*)>1
)n
on m.a = n.a and m.b = n.b
或
delete * from tb as m,
(
select a ,b
from tb
group by a , b
having count(*)>1
)n
where m.a = n.a and m.b = n.b








------------------------------------------------------------------------------------
在幾千條記錄里,存在著些相同的記錄,用SQL語句,刪除掉重復(fù)記錄
1、查找表中多余的重復(fù)記錄，重復(fù)記錄是根據(jù)單個(gè)字段（peopleId）來判斷
select * from people
where peopleId in (select? peopleId? from? people? group? by? peopleId? having? count(peopleId) > 1)

2、刪除表中多余的重復(fù)記錄，重復(fù)記錄是根據(jù)單個(gè)字段（peopleId）來判斷，只留有rowid最小的記錄
delete from people
where peopleId? in (select? peopleId? from people? group? by? peopleId?? having? count(peopleId) > 1)
and rowid not in (select min(rowid) from? people? group by peopleId? having count(peopleId )>1)

3、查找表中多余的重復(fù)記錄（多個(gè)字段）
select * from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq? having count(*) > 1)

4、刪除表中多余的重復(fù)記錄（多個(gè)字段），只留有rowid最小的記錄
delete from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多余的重復(fù)記錄（多個(gè)字段），不包含rowid最小的記錄
select * from vitae a
where (a.peopleId,a.seq) in? (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

比方說在A表中存在一個(gè)字段“name”，而且不同記錄之間的“name”值有可能會(huì)相同，
現(xiàn)在就是需要查詢出在該表中的各記錄之間，“name”值存在重復(fù)的項(xiàng)；
Select Name,Count(*) From A Group By Name Having Count(*) > 1

如果還查性別也相同大則如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
------------------------------------------------------------------------------------------------
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0

方法二
　　有兩個(gè)意義上的重復(fù)記錄，一是完全重復(fù)的記錄，也即所有字段均重復(fù)的記錄，二是部分關(guān)鍵字段重復(fù)的記錄，比如Name字段重復(fù)，而其他字段不一定重復(fù)或都重復(fù)可以忽略。
　　1、對(duì)于第一種重復(fù)，比較容易解決，使用
select distinct * from tableName
　　就可以得到無重復(fù)記錄的結(jié)果集。
　　如果該表需要?jiǎng)h除重復(fù)的記錄（重復(fù)記錄保留1條），可以按以下方法刪除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
　　發(fā)生這種重復(fù)的原因是表設(shè)計(jì)不周產(chǎn)生的，增加唯一索引列即可解決。

　　2、這類重復(fù)問題通常要求保留重復(fù)記錄中的第一條記錄，操作方法如下
　　假設(shè)有重復(fù)的字段為Name,Address，要求得到這兩個(gè)字段唯一的結(jié)果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
　　最后一個(gè)select即得到了Name，Address不重復(fù)的結(jié)果集（但多了一個(gè)autoID字段，實(shí)際寫時(shí)可以寫在select子句中省去此列）
select * from tablename where id in (
select id from tablename
group by id
having count(id) > 1)

轉(zhuǎn)載于:https://www.cnblogs.com/zhuawang/archive/2008/07/15/1243369.html

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