我正在嘗試編寫一個(gè)有很多比較的代碼

Write a program in “QUANT.C” which “quantifies” numbers. Read an integer “x” and test it, producing the

following output:

x greater than or equal to 1000 print “hugely positive”

x from 999 to 100 (including 100) print “very positive”

x between 100 and 0 print “positive”

x exactly 0 print “zero”

x between 0 and -100 print “negative”

x from -100 to -999 (including -100) print “very negative”

x less than or equal to -1000 print “hugely negative”

Thus -10 would print “negative”, -100 “very negative” and 458 “very positive”.

然后我嘗試使用開關(guān)解決它,但它不起作用,我是否必須使用if語句解決它或有一個(gè)方法來解決它使用開關(guān)？

#include

int main(void)

{

int a=0;

printf("please enter a number : \n");

scanf("%i",&a);

switch(a)

{

case (a>1000):

printf("hugely positive");

break;

case (a>=100 && a<999):

printf("very positive");

break;

case (a>=0 && a<100):

printf("positive");

break;

case 0:

printf("zero");

break;

case (a>-100 && a<0):

printf("negative");

break;

case (a-999):

printf("very negative");

break;

case (a<=-1000):

printf("hugely negative");

break;

return 0;

}

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